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krok68 [10]
3 years ago
14

I need help with these two questions numbers 7 and 8

Mathematics
1 answer:
Stolb23 [73]3 years ago
4 0
I think the answer for number 7 is 63.6 And for number 8 i think it is 379.94
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Please help me with this. I give brainliest and give ratings. Don't answer just to take my points or your getting reported
Maksim231197 [3]

Answer:

1/7 +5/9={1×9+5×7)/(9×7)=44/63is your answer

7 0
3 years ago
Describe a sequence of transformations that can be performed to polygon ABCDE to prove that it is similar to polygon FGHIJ
maxonik [38]

Answer:

answer below

Step-by-step explanation:

ABCDE go through dilation over center (6 , -2) with factor of 1/2 to FGHIJ

AB // FG slope: -2 , √20:√5 = 2: 1

BC // GH // X axis 8:4 = 2:1

CD // HI, slope= 1 , √8:√2 = 2:1

DE // IJ // x axis, 4:2 = 2:1

EA // JF // y axis, 2:1

8 0
3 years ago
Mary rolls two dice. She adds the numbers on the two dice. What is the chance of this sum being twelve?
jonny [76]

Answer:

10%

Step-by-step explanation:

sorry if u fail yeahh

5 0
3 years ago
Read 2 more answers
ANSWER ASAP PLZ!!
Vikentia [17]

\text{If is}\\\\\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2\end{array}

Answer:

\large\boxed{\left(-\dfrac{344}{69},\ -\dfrac{38}{3}\right)}

Step-by-step explanation:

\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2&\text{multiply both sides by (-0.3)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}0.2-0.3y=4\\-0.69x+0.3y=-0.36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-0.69x+0.2=3.64\qquad\text{subtract 0.2 from both sides}\\.\qquad-0.69x=3.44\qquad\text{divide both sides by (-0.69)}\\.\qquad x=-\dfrac{3.44\cdot100}{0.69\cdot100}\\.\qquad \boxed{x=-\dfrac{344}{69}}\\\\\text{Calculate the value of y from first equation:}

0.2-0.3y=4\qquad\text{subtract 0.2 from both sides}\\-0.3y=3.8\qquad\text{divide both sides by (-0.3)}\\y=-\dfrac{3.8\cdot10}{0.3\cdot10}\\\boxed{y=-\dfrac{38}{3}}

--------------------------------------------------------------------------

\text{If is}\\\\\left\{\begin{array}{ccc}0,2x-0,3y=4\\2.3x-y=1.2\end{array}\right

Answer:

\large\boxed{\left(-\dfrac{52}{7},\ -\dfrac{128}{7}\right)}

Step-by-step explanation:

\left\{\begin{array}{ccc}0.2x-0.3y=4&\text{multiply both sides by 10}\\2.3x-y=1.2&\text{multiply both sides by 10}\end{array}\right\\\\\left\{\begin{array}{ccc}2x-3y=40&\text{multiply both sides by (-10)}\\23x-10y=12&\text{multiply both sides by 3}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-20x+30y=-400\\69x-30y=36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad49x=-364\qquad\text{divide both sides by 49}\\x=-\dfrac{364:7}{49:7}\\.\qquad\boxed{x=-\dfrac{52}{7}}

2\left(-\dfrac{52}{7}\right)-3y=40\\-\dfrac{104}{7}-3y=40\qquad\text{multiply both sides by 7}\\-104-21y=280\qquad\text{add 104 to both sides}\\-21y=384\qquad\text{divide both sides by (-21)}\\y=-\dfrac{384:3}{21:3}\\\boxed{y=-\dfrac{128}{7}}

7 0
4 years ago
Work out 100-99 98-97 ... 4-3 2-1?
Verizon [17]
100-99=1
98-97=1
...
4-3=1
2-1=1

Any number subtracted from a number greater than it by one will always have the result of 1.

3 0
3 years ago
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