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3 years ago

Jake rolls a six-sided die, numbered 1 to 6, five times. He rolls a 3 on two attempts.

Mathematics

1 answer:

matrenka [14]3 years ago

4 0

I do believe that the answer to your question is 60%

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Find the exact value of cos 15°

Reil [10]

Answer:

$\frac{\sqrt{6}+\sqrt{2} }{4}$

Step-by-step explanation:

Using the difference formula for cosine and the exact values

cos45° = sin45° = $\frac{\sqrt{2} }{2}$ , cos30° = $\frac{\sqrt{3} }{2}$ , sin30° = $\frac{1}{2}$

cos(a - b) = cosacosb + sinasinb

Note 15° = 45° - 30°, thus

cos15°

= cos(45 - 30)°

= cos45°cos30° + sin45°sin30°

= ( $\frac{\sqrt{2} }{2}$ × $\frac{\sqrt{3} }{2}$ ) + ( $\frac{\sqrt{2} }{2}$ × $\frac{1}{2}$ )

= $\frac{\sqrt{6} }{4}$ + $\frac{\sqrt{2} }{4}$

= $\frac{\sqrt{6}+\sqrt{2} }{4}$

5 0

3 years ago

Read 2 more answers

I WILL THANKS YOU AND STAR YOU!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Serhud [2]

The answer is C. (3/4, -1/5)

8 0

3 years ago

A recursion formula and the initial term of a sequence are given. Write out the first five terms of the sequence. a Subscript fo

Lelu [443]

Answer:

6, -6, 6, -6 and 6.

Step-by-step explanation:

Given the recursion formula for a sequence

$a_{n+1}=-a_n\\$where a_1=6\\$

The first five terms of the sequence are:

$\text{First Term, }a_1=6\\$Second Term, a_2=a_{1+1}=-a_1=-6\\$Third term, a_3=a_{2+1}=-a_2=6\\$Fourth term, a_4=a_{3+1}=-a_3=-6\\$Fifth term, a_5=a_{4+1}=-a_4=6$

Therefore, the first five terms of the sequence:

$a_1,a_2,a_3,a_4,a_5=6, -6, 6, -6$ and 6.$

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3 years ago

Interquartile range n stuff

snow_lady [41]

Answer:

Can u add a better photo please

Step-by-step explanation:

3 0

3 years ago

I don’t get this at all can someone help?

aleksklad [387]

Reasons (In order):

Given
Given
Definition of a midpoint
Reflexive property
SAS
CPCTC

5 0

3 years ago