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ArbitrLikvidat [17]
3 years ago
6

I need help with this:What is the value of y? Enter your answer in the box. y =

Mathematics
1 answer:
lina2011 [118]3 years ago
3 0

Answer:

y=5 degrees

Step-by-step explanation:

It is an isosceles triangle so that means that there are two angles that equal 75, so that means the third side with 4y + 10 is equal to 30 degrees.

4y+10=30

4y=20

y=5 degrees

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Perimeter is the beat word to describe equal shares of shapes
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4 years ago
Write in expanded form 3 ways 23.56
AveGali [126]

Answer:

23+ .5 + .06

20+3+.56

10+10+ 3.56

Step-by-step explanation:

4 0
3 years ago
Solve the equation 2x2 + 13x + 15 = 0 by factoring. Show all steps.
natita [175]

Answer:

(2x + 3)(x + 5)

Step-by-step explanation:

2x² + 3x + 15 = 0

(2x + 3)(x + 5)

2x + 3 = 0

2x = -3

x = -3/2

x + 5 = 0

x = -5

4 0
3 years ago
A deck of ordinary cards is shuffled and 13 cards are dealt. What is the probability that the last card dealt is an ace?
alexandr1967 [171]

Answer:

The probability that the last card dealt is an ace is \frac{1}{13}.

Step-by-step explanation:

Given : A deck of ordinary cards is shuffled and 13 cards are dealt.

To find : What is the probability that the last card dealt is an ace?

Solution :

There are total 52 cards.

The total arrangement of cards is 52!.

There is 4 ace cards in total.

Arrangement for containing ace as the 13th card is 4\times 51!.

The probability that the last card dealt is an ace is

P=\frac{4\times 51!}{52!}

P=\frac{4\times 51!}{52\times 51!}

P=\frac{4}{52}

P=\frac{1}{13}

Therefore, the probability that the last card dealt is an ace is \frac{1}{13}.

4 0
3 years ago
supervisor records the repair cost for 25 randomly selected dryers. A sample mean of $93.36 and standard deviation of $19.95 are
Simora [160]
<h2><u>Answer with explanation:</u></h2>

The confidence interval for population mean (when population standard deviation is unknown) is given by :-

\overline{x}-t^*\dfrac{s}{\sqrt{n}}< \mu

, where n= sample size

\overline{x} = Sample mean

s= sample size

t* = Critical value.

Given : n= 25

Degree of freedom : df=n-1=24

\overline{x}= \$93.36

s=\ $19.95

Significance level for 98% confidence interval : \alpha=1-0.98=0.02

Using t-distribution table ,

Two-tailed critical value for 98% confidence interval :

t^*=t_{\alpha/2,\ df}=t_{0.01,\ 24}=2.4922

⇒ The critical value that should be used in constructing the confidence interval = 2.4922

Then, the 95% confidence interval would be :-

93.36-(2.4922)\dfrac{19.95}{\sqrt{25}}< \mu

=93.36-9.943878< \mu

=93.36-9.943878< \mu

=83.416122< \mu

Hence, the 98% confidence interval for the mean repair cost for the dryers. = 83.4161

4 0
3 years ago
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