3/8 of a lap is 1/32 of the entire race.
x - the number of laps in the race
There were 12 laps in the race.
Answer:
Answer:
you said you needed 22,23
22. y=7x-6
23. y=-x
Step-by-step explanation:
use math-way to put in the points
it explains for you
Step-by-step explanation:
Applying the percentages, and considering that 70% of the first group drinks at least 2 glasses of water a day, it is found that 0.725 = 72.5% of the team drinks at least 2 glasses of water a day.
The team is divided into two equal groups, hence, each represents 50%.
The <em>percentages </em>associated with drinking at least 2 glasses of water a day is:
- 70% of 50%(first group)
- 75% of 50%(second group)
Hence, applying the weighed percentage, the total percentage is:
0.725 = 72.5% of the team drinks at least 2 glasses of water a day.
A similar problem is given at brainly.com/question/1517088
Answer:
a. 9.5x + 6.5(x+c) < 8 when c>0
b. Must be one child more than the no. of adults.
Step-by-step explanation:
For Cinema 1:
for adult = $9.50
for child = $6.50
For Cinema 2:
Per person regardless of age = $8.00
First of all, we will find out the condition when per person rates in both cinema are equal.
Assume x = no. of adults
y = no. of children
Rate per person in Cinema I = Rate per person in Cinema II
(9.5x + 6.5y)/(x+y) = 8
9.5x + 6.5y = 8(x+y)
9.5x + 6.5y = 8x + 8y
9.5x-8x = 8y-6.5y
=> x = y
So rates are equal when no. of adults equals no. of children
For Cinema I to have better rates, no. of children should be atleast 1 more than the no. of adult. In this way the rate per person of Cinema I will be less than 8
Hence we form an inequality when y = x+c and c > 0
9.5x + 6.5(x+c) < 8 when c>0
Hence there must be 1 more children than the no. of adults attending Cinema I for it to be a better deal.
