The ages are consecutive even numbers.
The youngest child is (x+3) years old.
Every even number is 2 more than the one before it.
So the three ages are
(x + 3), (x + 5), and (x + 7).
Their sum is x+3 + x+5 + x+7 = 3x + 15
But we're told that their sum is 42, so we can write
3x + 15 = 42 <== the equation
Subtract 15 from each side: 3x = 27
Divide each side by 3 : x = 9 <== the solution
So the three ages are 12, 14, and 16.
The oldest child is 16 years old.
you don't have enough info, we need to know how old he was when he was twice her age, or how old she was
Answer:
6/5
Step-by-step explanation:
2/3 ÷ 5/9
2/3 × 9/5 ( while changing division to multiple, numerator and denominator changes
2 × 3/5 ( 9/3 =3
Ans =6/5
Answer:
26cm
Step-by-step explanation:
P= all sides
p=6+3+2+4+2+3+6
should get 26 then add the correct symbol...so put 26 <em><u>cm</u></em>
