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Naya [18.7K]
4 years ago
12

Set 1: 21, 24, 36, 38, 40, 42, 44, 63, 85

Mathematics
2 answers:
Aleksandr-060686 [28]4 years ago
8 0

Answer:

set 1 : 23.5

set 2 : 54

Step-by-step explanation:

lower quartile - upper quartile = answer

tatuchka [14]4 years ago
5 0

Answer:

set 1: 23.5

set 2: 54

Step-by-step explanation

edgu 2020

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3 years ago
Simplify 7(n+2)<br><br> A<br> 7n-14<br> B<br> -7n+14<br> C<br> n+9<br> D<br> 7n+14
zzz [600]

The answer is D, 7n + 14.

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5 0
3 years ago
Substitute each given value of the variable to find which, if any, is a solution of inequality.
OlgaM077 [116]

Given:

The inequalities are:

a) w

b) t>-25, t=-24, -25, -25.1, -27

To find:

The solution of inequalities by substituting the given values.

Solution:

a) We have,

w

After substituting the given values one by one, we get

-4.3 False statement.

-5.3 False statement.

-8.3 True statement.

-9 True statement.

Therefore the solutions of w are w=-8.3, -9.

b)

We have,

t>-25, t=-24, -25, -25.1, -27

After substituting the given values one by one, we get

-24>-25 True statement.

-25>-25 False statement.

-25.1>-25 False statement.

-27>-25 False statement.

Therefore, the solution of t>-25 is t=-24.

8 0
3 years ago
Which Line has The Greater Slope<br> 1<br> 2<br> 3<br> 4
mote1985 [20]
The answer to this question is line 1
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2 years ago
A triangle has base 2x+1 and height 6x-3. What value of x would give an area of 240m2?
GREYUIT [131]

Answer:

The values of x which would give an area of 240m² would be:

x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}

Step-by-step explanation:

Given

The base of triangle b = 2x+1

The height of triangle h = 6x-3

The Area of the triangle A = 240 m²

The Area of the triangle has the formula

A = 1/2 × b × h

substituting b = 2x+1, h = 6x-3 and A = 240

240\:=\:\frac{1}{2}\:\left(2x+1\right)\:\times \left(6x-3\right)

480=\left(2x+1\right)\left(6x-3\right)

480=12x^2-3

Subtract 480 from both sides

12x^2-3-480=480-480

12x^2-483=0

3\left(4x^2-161\right)=0

3\left(2x+\sqrt{161}\right)\left(2x-\sqrt{161}\right)=0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

2x+\sqrt{161}=0\quad \mathrm{or}\quad \:2x-\sqrt{161}=0

solving

2x+\sqrt{161}=0

2x=-\sqrt{161}

Divide both sides by 2

\frac{2x}{2}=\frac{-\sqrt{161}}{2}

x=-\frac{\sqrt{161}}{2}

also solving

2x-\sqrt{161}=0

2x=\sqrt{161}

Divide both sides by 2

\frac{2x}{2}=\frac{\sqrt{161}}{2}

x=\frac{\sqrt{161}}{2}

Therefore, the values of x which would give an area of 240m² would be:

x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}

3 0
3 years ago
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