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Irina18 [472]
3 years ago
11

From eight different books, in how many ways can any four of them be arranged side by side on a bookshelf?

Mathematics
1 answer:
Snezhnost [94]3 years ago
3 0
First we calculate how many ways you can choose four books from a set of eight.
We use the formula n! / [r! * (n-r)!]

8! / [4! * 4!]

= 8*7*6*5 / 4*3*2*1 = 70 ways

Then we have to calculate how many permutations can be made from 4 objects which equals 4*3*2*1 = 24

So, the TOTAL number of ways = 70 * 24 = 1,680


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Answer: x+3y=12

Step-by-step explanation:

Slope of two lines that are perpendicular to each other is 1.

If one line is y=3x, then its slope = 3   [by comparing to the linear equation y= mx+c, here m=3]

Let n be the slope of the required line, then

n\times3=-1\\\\\rightarrow\ n=\dfrac{-1}{3}

Equation of line with slope n and passers through (a,b) is

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Equation of line with slope n= \dfrac{-1}{3} and passes through point ( 0,-4) :

(y-(-4))=\dfrac{-1}{3}(x-0)\\\\\Rightarrow\ y+4=\dfrac{-1}{3}x\\\\\Rightarrow\ -3(y+4)=x\\\\\Rightarrow-3y-12=x\\\\\Rightarrow x+3y=12

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Four undiscernable choices: 25% chance of guessing correctly -- Expectation: 0.25*(1) + 0.75*(-1) = -0.50

I'll use 0.33 as an approzimation for 1/3

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And thus we see that only if you can remove three is guessing neutral. There is no time when guessing is advantageous.

One Correct Answer: 100% chance of guessing correctly -- Expectation: 1.00*(1) + 0.00*(-1) = 1.00

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