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Marizza181 [45]
3 years ago
14

Find the equation of the line that is perpendicular to the line x = −5 and passes through the point (1, 3.14).

Mathematics
1 answer:
kodGreya [7K]3 years ago
4 0

Answer:

A

Step-by-step explanation:

Perpendicular to x = -5 is going to be a horizontal line.

Since it passes through (1,3.14),

Equation is y = 3.14

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11 divided by 3 equals 3.66 repeating
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=<br><br> help me please<br> thx so much<br> have a good one
bezimeni [28]

Answer:

2(2x + 5)(2x - 5)

Step-by-step explanation:

2(2x + 5)(2x - 5)

= (4x + 10)(2x - 5)

= 8x² - 20x + 20x - 50

= 8x² - 50

3 0
3 years ago
Y is greater than or equal to -×-5
Katen [24]

Answer:

Y<u>></u>-x-5

Step-by-step explanation:

6 0
3 years ago
K is the midpoint of PQ, P has
Pachacha [2.7K]

Answer:

Coordinates of Q (x_2,y_2) \:are\: \mathbf{(7,16)}

Option D is correct option.

Step-by-step explanation:

We are given:

K is the midpoint of PQ

Coordinates of P = (-9,-4)

Coordinates of K = (-1,6)

We need to find coordinates of Q  (x_2,y_2)

We will use the formula of midpoint: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

We are given midpoint K and x_1,y_1 the coordinates of P we need to find x_2,y_2 the coordinates of Q.

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\(-1,6)=(\frac{-9+x_2}{2},\frac{-4+y_2}{2})\\

Now, we can write

-1=\frac{-9+x_2}{2}, 6=\frac{-4+y_2}{2}\\Simplifying:\\-2=-9+x_2\:,\: 12=-4+y_2\\-2+9=x_2\:,\: 12+4=+y_2\\x_2=7\:,\:y_2=16

So, we get coordinates of Q (x_2,y_2) \:are\: \mathbf{(7,16)}

Option D is correct option.

6 0
3 years ago
WILL MARK YOU BRAINLIEST !!!!
liq [111]

Answer:

\overline {PM} \cong \overline {ON} because they are opposite sides of a parallelogram.

Step-by-step explanation:

First of all, let us have a look at the definition of a parallelogram.

<em>A parallelogram is a closed 4 sided figure (i.e. a quadrilateral) made up with two pairs of straight lines such that the two pairs are parallel and equal to each other.</em>

<em></em>

For example, let us consider a quadrilateral ABCD as attached in the diagram in answer area.

The two pair of lines are:

AB,  DC and BC, AD

For ABCD to be a parallelogram, the lines

AB and DC must be parallel to each other and AB = DC

AND

BC and AD must be parallel to each other and BC = DA

------------------------------

In the given question, we are given that the quadrilateral MNOP is a parallelogram.

The two pairs opposite lines are OP, NM and PM, ON.

As per the definition of a parallelogram,

OP and NM must be <em>parallel and equal </em>to each other.

AND

PM and ON must be <em>parallel and equal </em>to each other.

\therefore \overline {PM} \cong \overline {ON}.

Hence proved.

6 0
3 years ago
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