Question

Eight two-person teams are participating in a three-legged race. Find the number of orders in which all 8 teams can finish the race.

Answer 1

Each team needs two people for a 3-legged race.
Therefore, the number of orders (combinations) of 2 people at a time from 8 is
₈C₂ = 8!/(2!6!)
      = (8*7*6!)/(2*6!)
      = (8*7)/2
      = 56/2
      = 28

Answer: 28