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torisob [31]
3 years ago
15

Eight two-person teams are participating in a three-legged race. Find the number of orders in which all 8 teams can finish the r

ace.
Mathematics
1 answer:
Wewaii [24]3 years ago
8 0
Each team needs two people for a 3-legged race.
Therefore, the number of orders (combinations) of 2 people at a time from 8 is
₈C₂ = 8!/(2!6!)
      = (8*7*6!)/(2*6!)
      = (8*7)/2
      = 56/2
      = 28

Answer: 28
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What is the value of x in the equation 8 + x = 3?<br><br> −5<br> 5<br> 11<br> 24
Dvinal [7]

Answer: 8 + x = 3

To solve for this, we need to get x by itself on one side of the equation.

Currently, we have 8 being added to x, so we need to perform the opposite order of equations to get rid of 8.

The opposite of +8 is -8, so subtract 8.

Remember, if you add, subract, multiply or divide by any new number, you must do it to both sides of the equation.

8 + x = 3

Subtract 8 from both sides.

8 - 8 = 0

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We're now left with:

x = -5

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Step-by-step explanation:

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