Answer: Hope this helps you.
1,3
Step-by-step explanation:
(6, 4) and (0,2)
4-2/6-0 =2,6 (1,3)
3^15 = 14,348,907
Which means...
x^5 = 14,348,907
If we execute
and do the same with x^5 we get...
x = 27
So the 5th power of <u>27</u> is equal to 3^15.
⭐ Answered by Hyperrspace (Ace) ⭐
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Answer:
A and B. See explanation
C. x=4
Step-by-step explanation:
A: Consider two functions
and
The point of intersection of the graphs of these two functions is the solution of the system ![\left \{ {{y=2^x} \atop {y=4^{x-2}}} \right.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7By%3D2%5Ex%7D%20%5Catop%20%7By%3D4%5E%7Bx-2%7D%7D%7D%20%5Cright.)
When you are solving this system, you have to equate the right sides of these equations and get
So, the x-coordinate of the point of intersection is the solution of the equation ![2^x=4^{x-2}.](https://tex.z-dn.net/?f=2%5Ex%3D4%5E%7Bx-2%7D.)
B.
![\begin{array}{ccccccc}x&-1&0&1&2&3&4\\2^x&\frac{1}{2}&1&2&4&8&16\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bccccccc%7Dx%26-1%260%261%262%263%264%5C%5C2%5Ex%26%5Cfrac%7B1%7D%7B2%7D%261%262%264%268%2616%5Cend%7Barray%7D)
![\begin{array}{ccccccc}x&-1&0&1&2&3&4\\4^{x-2}&\frac{1}{64}&-\dfrac{1}{16}&\dfrac{1}{4}&1&4&16\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bccccccc%7Dx%26-1%260%261%262%263%264%5C%5C4%5E%7Bx-2%7D%26%5Cfrac%7B1%7D%7B64%7D%26-%5Cdfrac%7B1%7D%7B16%7D%26%5Cdfrac%7B1%7D%7B4%7D%261%264%2616%5Cend%7Barray%7D)
C. Graphically, graphs intersect at point (4,16), so x=4 is the solution of the equation
-6x + 5 + 12x - 6
-6x + 12 + 5 - 6
6x - 1
2(x - 9) + 6(-x + 2) + 4x
2(x) - 2(9) + 6(-x) + 6(2) + 4x
2x - 18 - 6x + 12 + 4x
2x - 6x + 4x - 18 + 12
-4x + 4x - 6
6
3x² + 12 + 9x - 20 + 6x² - x
3x² + 6x² + 9x - x + 12 - 20
9x² + 8x - 8
(x + 2)(x + 4) + (x + 5)(x - 1)
(x² + 4x + 2x + 8) + (x² - x + 5x - 5)
(x² + 6x + 8) + (x² + 4x - 5)
(x² + x²) + (6x + 4x) + (8 - 5)
2x² + 10 + 3
(x²y)(xy²)
(x²⁺¹y¹⁺²)
x³y³
(-x²y²)(xy²)
(-x²⁺¹y²⁺²)
-x³y⁴