Given:
m(ar QT) = 220
m∠P = 54
To find:
The measure of arc RS.
Solution:
PQ and PT are secants intersect outside a circle.
<em>If two secants intersects outside a circle, then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.</em>
Multiply by 2 on both sides.
Subtract 220 from both sides.
Multiply by (-1) on both sides.
The measure of arc RS is 112.
Answer:
176000cm
Step-by-step explanation:
1.76km * 1000m / 1km * 100cm / 1m = 176000cm
For this case we have the following function:
![s (V) = \sqrt [3] {V}](https://tex.z-dn.net/?f=s%20%28V%29%20%3D%20%5Csqrt%20%5B3%5D%20%7BV%7D)
This function describes the side length of the cube.
If Jason wants a cube with a minimum volume of 64 cubic centimeters, then we propose the following inequality:
![s \geq \sqrt [3] {64}](https://tex.z-dn.net/?f=s%20%5Cgeq%20%5Csqrt%20%5B3%5D%20%7B64%7D)
Rewriting we have:
![s \geq \sqrt [3] {4 ^ 3}\\s \geq4](https://tex.z-dn.net/?f=s%20%5Cgeq%20%5Csqrt%20%5B3%5D%20%7B4%20%5E%203%7D%5C%5Cs%20%5Cgeq4)
Answer:
Option B
Answer: A
n-4(32.5) > 300;n > 430tep-by-step explanation:
given that Zack wants to make a profit of more than $300 for painting 4 identical rooms. That is
Profit > $300
Then, the profit he makes is equal to the amount he is paid minus the cost of supplies. The cost of supplies is $32.50 for each room. That is
n - 32.5 and
P + 32.5 × 4
Where 4 = number of rooms
P + 130
The minimum profit = 300 + 130 = $430
Therefore, the inequality and solution that represent the dollar amount, n, that zack must be paid for each room if he is to make a profit of more than 300$ is
n-4(32.5) > 300;n > 430
I would say B because you are going towards the negative side which is to the left!
hope that helped!!
:)
