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prisoha [69]
3 years ago
11

How to answer this on descending powers of x please help pretty please

Mathematics
1 answer:
zheka24 [161]3 years ago
4 0

Answer:  25x² - 64

<u>Step-by-step explanation:</u>

  (5x + 8)(5x - 8)

=        5x(5x - 8)   +    8(5x - 8)

=      25x² - 40x    +    40x - 64

=      25x²         + 0x           - 64

=              \large\boxed{25x^2-64}

NOTE: descending powers means the biggest exponent goes first, then the next biggest exponent, etc.

For example: x⁴ then x³ then x² then x then the number (which is actually x⁰)

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NEED ANSWER ASAP!!! WILL GIVE BRAINLIEST TO WHO ANSWERS FIRST!
alexandr1967 [171]

Answer:

x < - 4

Step-by-step explanation:

Given

2x - 2 > 4x + 6 ( subtract 2x from both sides )

- 2 > 2x + 6 ( subtract 6 from both sides )

- 8 > 2x ( divide both sides by 2 )

- 4 > x , thus

x < - 4

8 0
2 years ago
What is the justification for step 2 in the solution process?
Maksim231197 [3]

Answer:

Subtract property of deviation becasue your subtracting 6y frrom both sides of the equation.

Step-by-step explanation:

1)Given: 12y - 40 - 4y = 6y - 18

2)Simplify by adding 12y + (-4y): 8y - 40 = 6y - 18

3)Subtract property of deviation: 8y -6y - 40 = 6y -6y - 18

2y - 40 = -18

<em>Hope this helped!</em>

8 0
2 years ago
Read 2 more answers
Vertex: <br> (<br> 2<br> ,<br> 0<br> )<br> , Passes through: <br> (<br> 5<br> ,<br> −<br> 18<br> )
NemiM [27]

Answer:

2>0                5>-18

Step-by-step explanation:

8 0
2 years ago
Select the postulate that proves this fact.
zimovet [89]

Answer:

Postulate 1a: A plane contains at least three points not all on one line.

Step-by-step explanation:

5 0
2 years ago
Show that the equation x^3+6x-5=0 has a solution between x=0 and x=1
Mnenie [13.5K]

Answer:

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

Step-by-step explanation:

The equation f(x) given is:

f(x) = x^3+6x-5

For x = 0. the value of the expression is:

f(0) = 0^3+0-5\\f(0) = -5

For x = 1, the value of the expression is:

f(1) = 1^3+6-5\\f(1)=2

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

In other words, there is at least one solution for the equation between x=0 and x=1.

6 0
2 years ago
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