To simulate the probability in a spinner divide the spinner into colors depending on the probability each color represents.
<h3>What does the word "probability" mean?</h3>
This word refers to the likelihood for an event to occur. Moreover, it is often expressed either as a fraction, a percentage, or a number.
<h3>How to create a spinner to simulate probability?</h3>
In this case, each of the colors represents a probability:
- Green 20%
- Blue 1/4 or 25%
- Yellow 2/5 oe 40%
- Orange 15%
Due to this, the best is to divide the spinner by colors and considering the percentanges of each color. For example 40% of the spinner should be red, while 15% should be orange.
Learn more about spinner in: brainly.com/question/24280611
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Hi,
You just have to change z^25 to z^24 or z^27.
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
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Answer:
Step-by-step explanation:
f(x) -h(x) = x³ + 2x² -7x - 8 - [4x² - x - 15 ]
= x³ + 2x² - 7x - 8 - 4x² + x + 15
= x³ + 2x² - 4x² - 7x + x - 8 + 15
= x³ - 2x² - 6x + 7
