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ki77a [65]
3 years ago
10

What is 1/4 of 697 rounder to the nearest integer

Mathematics
2 answers:
dem82 [27]3 years ago
4 0

Answer:

rounder to the nearest integer is 174

Step-by-step explanation:

1/4 of 697 = 174.25

0.25 is under 0.50

GREYUIT [131]3 years ago
4 0

Answer:

174

Step-by-step explanation:

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2, Find the price of a a video game that costs $60.00 with 30% discount.
Pie

Answer:

18$

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p
Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Item a:

The estimate is \pi = 0.213 - 0.195 = 0.018.

The sample size is <u>n for which M = 0.03</u>, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}

\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2

n = 53.1

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence \pi = 0.05

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 751.7

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0
2 years ago
Expect a ton of trigonometry questions from this account. i know absolutely nothing
Paha777 [63]

Answer:

see attached formulas

Step-by-step explanation:

Math is beautiful. Have fun learning.

8 0
2 years ago
PLZZ HELP OR IM FAILLING
Verizon [17]

Answer:

17/ 30 ???

Step-by-step explanation:

.....................

4 0
3 years ago
Read 2 more answers
If a toy rocket is launched vertically upward from the ground level with an initial velocity of 128 feet per second, then its he
natta225 [31]

Answer:

The maximum height of the rocket is 256 feet

Step-by-step explanation:

The vertex form of the quadratic function f(x) = ax² + bx + c is

f(x) = a(x - h)² + k, where

  • (h, k) is the vertex point
  • h = \frac{-b}{2a} and k = f(h)
  • (h, k) is a minimum point if a > 0 and a maximum point if a < 0

Let us use these rules to solve the question

∵ h(t) = -16t² + 128t

→ Compare it by the form of the quadratic function above

∴ a = -16 and b = 128

∵ a < 0

∴ The vertex (h, k) is a maximum point

∴ The maximum height of the rocket is the value of k

→ Use the rule of h above to find it

∵ h = \frac{-128}{2(-16)} = \frac{-128}{-32}

∴ h = 4

→ Substitute x in the equation by the value of h to find k

∵ k = h(h)

∴ k = -16(4)² + 128(4)

∴ k = -256 + 512

∴ K = 256

∴ The maximum height of the rocket is 256 feet

4 0
3 years ago
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