Answer:
{24, 18, 12, 6, 0} is the range of the above function
Step-by-step explanation:
solution:
let, x= -4
f(-2) = 12-3*(-2)
= 12+12
=24
let,x= -2
f(-2) = 12-3*(-2)
=12+6
18
let,x =0
f(0)= 12-3*0
=12-0
=12
let,x=2
f(2) = 12-3*2
=12-6
=6
let,x=4
f(4) = 12-3*4
=12-12
=0
Answer:
Step-by-step explanation:
If x - 1 is a factor of the cubic, then 1 should result in 0 when you put it in the cubic for x. Does it?
f(1) = 2(1)^3 - 15(1)^2 + 22(1) + 15
f(1) = 2 - 15 + 22 + 15
f(1)= 24.
No the result is not zero. So x - 1 is not a factor.
However there must be something that makes this cubic go to zero. The easiest way to find it is to graph it.
The numbers that do make this zero are -0.5, 3, 5
Which mean that the factors are (2x+1)(x-3)(x - 5)
Answer:
I think it is 2/ 15 pls mark as breanliest
Answer:
PI is the the area around the circumfrance. It is equal to 3.14.