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Alexxandr [17]
4 years ago
12

Circle P has a circumference of approximately 75 inches.

Mathematics
1 answer:
snow_tiger [21]4 years ago
5 0

Answer:

12

Step-by-step explanation

to find radius

take the 75 and divide by pi, which gives you a 23.88 diameter. radius is half of the diameter

so 23.88 is 11.94

or 12 when rounded

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Lady_Fox [76]

Answer:

Step-by-step explanation:

Well is she wanted to make $80 “b” she would have to garden for 16 hours to make a maximum of $80

“C” if she wanted to make it out of babysitting she would have to work the same for 8 hours if she babysit

Workout : b part = 10+10+10+10+10+10+10+10 Key:10=2

:c part = 20+20+20+20. Key:20=2

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Find the roots of the following equations.<br> a) 4x+9=34<br> b) (x-4)(x+2)=0<br> c) 2x^2-6x+4=0
Masteriza [31]
A. 4x + 9 = 34
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7 0
3 years ago
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skelet666 [1.2K]

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Assume that 155 students are surveyed and every student takes at least one of the following languages. The results of the survey
balu736 [363]

Answer:

91 people take Russian

26 people take French and Russian but not German

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the students that take French.

-The set B represents the students that take German

-The set C represents the students that take Russian.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a is the number of students that take only Franch, A \cap B is the number of students that take both French and German , A \cap C is the number of students that take both French and Russian and A \cap B \cap C is the number of students that take French, German and Russian.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following subsets:

a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)

There are 155 people in my school. This means that:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 155

The problem states that:

90 take Franch, so:

A = 90

83 take German, so:

B = 83

22 take French, Russian, and German, so:

A \cap B \cap C = 22

42 take French and German, so:

A \cap B = 42 - (A \cap B \cap C) = 42 - 22 = 20

41 take German and Russian, so:

B \cap C = 41 - (A \cap B \cap C) = 41 - 22 = 19

22 take French as their only foreign language, so:

a = 22

Solution:

(1) How many take Russian?

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

C = c + (A \cap C) + 19 + 22

C = c + (A \cap C) + 41

First we need to find A \cap C, that is the number of students that take French and Russian but not German. For this, we have to go to the following equation:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

90 = 22 + 20 + (A \cap C) + 22

(A \cap C) + 64 = 90.

(A \cap C) = 26

----------------------------

The number of students that take Russian is:

C = c + 26 + 41

C = c + 67

------------------------------

Now we have to find c, that we can find in the equation that sums all the subsets:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 155

22 + b + c + 20 + 26 + 19 + 22 = 155

b + c + 109= 155

b + c = 46

For this, we have to find b, that is the number of students that take only German. Then we go to this eqaution:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

B = b + 19 + 20 + 22

B = b + 61

b + 61 = 83

b = 22

-------

b + c = 46

c = 46 - b

c = 24

The number of people that take Russian is:

C = c + 67

C = 24 + 67

C = 91

91 people take Russian

(2) How many take French and Russian but not German?

(A \cap C) = 26

26 people take French and Russian but not German

4 0
3 years ago
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