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Elanso [62]
3 years ago
8

Select the correct answer.

Mathematics
1 answer:
iris [78.8K]3 years ago
5 0

Answer:

P' (2, -4)

Q' (3, -1)

R' (4, -4)

Step-by-step explanation:

Reflection in the y axis

(x, y) → (-x, y)

P(⁻²₋₄ ) → P'(²₋₄ ) ∴ P'(2, -4)

Q(⁻³₋₁ ) → Q'(³₋₁ ) ∴ Q'(3, -1)

R(⁻⁴₋₄ ) → R'(⁴₋₄ ) ∴ R'(4, -4)

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PLEEASSSSEEEE HHEEEEELLLLPPPPPPPP !!!!!!!!!!!!!!!!!!!!!!!!!!! Circle R is shown. Line segments Q R and S R are radii. The length
Inessa [10]

Answer:

144\pi\ un^2.

Step-by-step explanation:

In the attached diagram, circle R is shown. Line segments QR and SR are radii and QR = SR = 18 units.

The measure of the central angle QRS is \dfrac{8\pi}{9}

1. Find the area of the whole circle:

A_{circle}=\pi r^2=\pi \cdot 18^2=324\pi \ un^2.

2. Note that the whole circle is determined by the full rotation angle with measure 2\pi radians. So,

\begin{array}{cc}\text{Angle}&\text{Area}\\ \\2\pi &324\pi \\ \\\dfrac{8\pi }{9}&A_{sector}\end{array}

So, write a proportion:

\dfrac{2\pi}{\frac{8\pi}{9}}=\dfrac{324\pi}{A_{sector}}

Cross multiply

2\pi \cdot A_{sector}=324\pi \cdot \dfrac{8\pi }{9}\\ \\A_{sector}=162\pi \cdot \dfrac{8}{9}=144\pi\ un^2.

4 0
3 years ago
Read 2 more answers
2+2=x<br><br> a.3<br> b.9<br> c,5<br> d.4
zavuch27 [327]

Answer:

D. 4

Step-by-step explanation:

2 + 2 = 4

7 0
3 years ago
3x−12≥15<br><br> 2x−5≤9<br><br> 5x+8≤53<br><br> 3x−5≥16
zalisa [80]

Answer:

Step-by-step explanation:

A) 3x−12≥15

3x ≥ 15 + 12

3x ≥ 27

or x≥ 9

B) 2x−5≤9

2x ≤ 9 +5

2x ≤ 14

or x ≤ 7

C) 5x+8≤53

5x ≤ 53 -8

5x ≤ 45

or x ≤ 9

D) 3x−5≥16

3x ≥ 16 + 5

3x ≥ 21

or x ≥ 7

Have a good day!

8 0
3 years ago
PLEASE HELP!!
Dima020 [189]

Answer:

A. 90°+m∠4

Step-by-step explanation:

Also  

∠ A + ∠ C = 180  o = ∠ B + ∠ D

⇒ 2 x+ ( 3 x − 5 ) = 180  0 = ( x + 5 ) +  ∠  C

5 x  −  5  =  180

Add 5 to both sides

5 x  =  185

Divide both sides by 5

x =  185  5  =  37

But it was A. 90°+m∠4

4 0
3 years ago
2.) Solve 48 = -6<br>4.) Solve 4 + 3.5 = 12.5​
3241004551 [841]
These aren't solvable.
5 0
3 years ago
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