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3 years ago

Simplify 16-3(8-3)^2÷5

Mathematics

2 answers:

Darina [25.2K]3 years ago

6 0

Answer:

Step-by-step explanation:

PODMAS:-

16-3(8-3)²/5

=16-3(5)²/5

=16-3(25)/5

=16-3(5)

=16-15

= 1

Sunny_sXe [5.5K]3 years ago

6 0

Answer:

Step-by-step explanation:

=> $\frac{16-3(8-3)^2}{5}$

=> $\frac{13(5)^2}{5}$

=> $\frac{13(25)}{5}$

=> 13 × 5

=> 65

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yKpoI14uk [10]

Answer:

V = 8,181.23 $cm^{3}$

Step-by-step explanation:

Unfortunately, we are not given any answer choices to choose from but using the information provided we can find the actual volume of the basketball. A basketball is made in the shape of a sphere and the formula for the volume of a sphere is the following...

V = $\frac{4}{3} * \pi * r^{3}$

radius of a circle/sphere is half of it's diameter. Since we are provided the diameter size we simply divide it by 2 which would give us 12.5cm. Now we simply plug this value into the formula and solve for V.

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3 years ago

an art student wants to make a model of an ancient building. the length of the building is 1.6 times its width. The length of th

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I think it would be 17.5in

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3 years ago

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Snezhnost [94]

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)

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3 years ago

Suppose that a recent article stated that the mean time spent in jail by a first-time convicted burglar is 2.5 years. A study wa

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Using the z-distribution, it is found that since the test statistic is greater than the critical value, it can be concluded that the mean length of jail time has increased.

At the null hypothesis, it is tested if the mean length of jail time is still of 2.5 years, that is:

$H_0: \mu = 2.5$

At the alternative hypothesis, it is tested if it has increased, that is:

$H_1: \mu > 2.5$

We have the standard deviation for the population, thus, the z-distribution is used. The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
$\sigma$ is the standard deviation of the sample.
n is the sample size.

For this problem, the values of the parameters are: $\overline{x} = 3, \mu = 2.5, \sigma = 1.5, n = 26$

Hence, the value of the test statistic is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

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$z = 1.7$

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05, is of $z^{\ast} = 1.645$

Since the test statistic is greater than the critical value, it can be concluded that the mean length of jail time has increased.

A similar problem is given at brainly.com/question/24166849

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2 years ago

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Answers:

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2 years ago