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Brrunno [24]
3 years ago
13

3/4 (x +21) = 10 1/2 What does x equal?

Mathematics
2 answers:
Elena L [17]3 years ago
3 0

Answer:

\huge \boxed{ \boxed{ \red{x  =  - 7}}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • equation
  • PEMDAS
<h3>let's solve:</h3>
  1. \sf distribute :  \\  \frac{3 x+ 63}{4}  =  10\frac{1}{2}
  2. \sf simplify \: mixed \: fraction :  \\  \frac{3x + 63}{4}  =  \frac{21}{2}
  3. \sf cross \: multipication :  \\ 2(3x + 63) = 84
  4. \sf distribute \: 2 :  \\ 6x + 126 = 84
  5. \sf cancel \: 126 \: from \: both \: sides :  \\ 6x + 126 - 126 = 84 - 126 \\ 6x =  - 42
  6. \sf divide \: both \: sides \: by \: 6 :  \\  \frac{6x}{6}  =  \frac{ - 42}{6}  \\  \bcancel{\frac{6x}{6} } =  \frac{ \cancel{ - 42}  \: ^{ - 7} }{  \cancel{ \: 6}}  \\   \therefore \: x =  - 7
bagirrra123 [75]3 years ago
3 0

Step-by-step explanation:

Solution given;

\frac{3}{4} (x + 21) = 10 \frac{1}{2 }  \\ 3x + 63 =  \frac{21}{2}  \times 4 \\ 3x = 42 - 63 \\ x =  \frac{ - 21}{3}  \\ x =  - 7

:.x=-7 is your answer.

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Gnesinka [82]

The real solutions the equation as given in the task content; x² = 225 are; +25 and -25.

<h3>What are the real solutions of the equation as given in the task content?</h3>

It follows from the task content that the real solutions of the equation as given in the task content can be determined as follows;

x² = 225

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Therefore, the real solutions of the equation are; +25 and -25.

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A rope 13 meters long will just reach from the top of a flagpole to a point on the ground 12 meters from teh base of the flagpol
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Answer:

the height of the flagpole is 5 meters

Step-by-step explanation:

The computation of the height of the flagpole is given below

Given that

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