Answer:
y=1/8x+6
Step-by-step explanation:
y-y1=m(x-x1)
y-9=1/8(x-24)
y=1/8x-24/8+9
y=1/8x-3+9
y=1/8x+6
The answer is 7 R 4! hoped this helps!
7 devide by k in algebric function = 7/k
Answer:
m < amc = 54°
Step-by-step explanation:
< amb and < bmc are complementary angles whose sum equals 90°.
Therefore, to find the value of 2x°, we must first solve for x.
We can establish the following equality statement:
< amb + < bmc = < amc
< 2x° + (x + 9)° = 90°
Combine like terms:
2x° + x° + 9° = 90°
3x° + 9° = 90°
Subtract 9 from both sides:
3x° + 9° - 9° = 90° - 9°
3x = 81°
Divide both sides by 3 to solve for x:
3x/3 = 81°/3
x = 27°.
Since x = 27°, substitute its value into 2x° to find m < amc:
2x° = 2(27°) = 54°
Therefore, m < amc = 54°
Please mark my answers as the Brainliest, if you find this helpful :)
Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
