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Semmy [17]
3 years ago
15

0.91÷81.75 can someone help please

Mathematics
2 answers:
grin007 [14]3 years ago
6 0
89.8351648352 is your answer<span>
</span>
Leokris [45]3 years ago
3 0
0.0111314985 I think that's the answer
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What is the volume of the cylinder below?
MrRissso [65]
I think it would be 175
4 0
3 years ago
Two business partners, Alan and Rob, invested money in their business at a ratio of 6 to 7. Bob invested the greater amount. The
Verdich [7]

Answer:

180 Alan, 210 Rob

Step-by-step explanation:

6+7= 13

390÷13= 30

30×6=180 =Alan

30××7=210 =Rob

4 0
4 years ago
Translate this sentence into an equation.
motikmotik

Answer:

g = 61.

Step-by-step explanation:

g + 9 = 70             Subtract 9 from both sides of the equation:

g + 9 - 9 = 70 - 9

g = 61.

4 0
4 years ago
Solve the system of equations below algebraically <br> 2x+3y=6 and -5x+2y=4
Charra [1.4K]


Steps
I’m using elimination so I’m trying to get rid of y
To do that I multiply the first equation by 2 and the second by -3. Then solve
4x + 6x = 12
15x + -6x = -12
—————————
19x + 0 = 0
Divid by 19 to get x to one side. 0/19 is 0 so
X= 0
Plug that into an equation so 0 + 3y = 6
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7 0
3 years ago
A quadratic equation is shown below:
sweet [91]

Answer:

Part A:

( 1.8333, -0.08333)

Part B:

x = 2 or x = 5/3

Step-by-step explanation:

The quadratic equation

3x^{2}-11x+10=0 has been given.

Part A:

We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.

\frac{d}{dx}(3x^{2}-11x+10)=6x-11

Setting the derivative to 0;

6x - 11 = 0

6x = 11

x = 11/6

The corresponding y value is determined by substituting x = 11/6 into the original equation;

y = 3(11/6)^2 - 11(11/6) + 10

y = -0.08333

The vertex is thus located at the point;

( 1.8333, -0.08333)

Find the attached

Part B:

We can use the quadratic formula to solve for x as follows;

The quadratic formula is given as,

x=\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}

From the quadratic equation given;

a = 3, b = -11, c = 10

We substitute these values into the above formula and simplify to determine the value of x;

x=\frac{11+/-\sqrt{11^{2}-4(3)(10) } }{2(3)}=\frac{11+/-\sqrt{1} }{6}\\\\x=\frac{11+/-1}{6}\\\\x=\frac{11+1}{6}=2\\\\x=\frac{11-1}{6}=\frac{5}{3}

6 0
4 years ago
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