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a_sh-v [17]
3 years ago
9

Which points could be on the line that is parallel to and passes through point J? Check all that apply.

Mathematics
2 answers:
Mandarinka [93]3 years ago
4 0
Here we're finding the equation of a 'new' line which passes thru (1,3) and is parallel to the orange line.  We need the slope of the orange line, which will also be the slope of the new line thru J.
        -2 - 1       -3
m = --------- = ------ = -1/2
         2-(-4)       6

Then the equation of the new line, in point-slope form, is

y - 3 = (-1/2)(x - 1).
Rama09 [41]3 years ago
3 0
(-3,5),(3,2), and (5,1), I believe
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At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel
Alexeev081 [22]
Use Law of Cooling:
T(t) = (T_0 - T_A)e^{-kt} +T_A
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
42 = (80-20)e^{-3k} +20 \\  \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\  \\ k = -\frac{1}{3} ln (\frac{11}{30})

Substituting k back into cooling equation gives:
T(t) = 60(\frac{11}{30})^{t/3} + 20

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\  \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80
Solve for x:
x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80
Sub back into original cooling equation, x = T(t)
-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20
Solve for t:
60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3}  = 60 \\  \\  (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\  \\  \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\  \\ \\  t = 4.959

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
8 0
3 years ago
What number is 20% of 40?
VladimirAG [237]

Answer:

It would be 8

Step-by-step explanation:

20% of 40 is 8

6 0
3 years ago
Read 2 more answers
Dina and Masha start cycling on a 20 km bike path at the same time. When Dina reaches the end of the path, Masha still has 4 km
sammy [17]

Answer:

0.5 hour

Step-by-step explanation:

Given

Speed of Dina = 10 km/h

Distance = 20 km

So the time Dina taken to complete the track is:

Speed=\frac{distance}{time}\\10=\frac{20}{time}\\time=\frac{20}{10}\\ time=2\ hours

The time taken by Dina is 2 hours. As masha started with dina but she was 4 km of the path left to cycle,

her distance covered in 2 hours was:

Distance\ covered\ by\ Masha\ in\ 2\ hours=20-4\\=16 km

So we know the time and distance:

Now,

Speed\ of\ Masha=\frac{distance}{time}\\ =\frac{16}{2}\\ =8\ kilometer\ per\ hour

We have to calculate the time that will be needed by MAsha to complete the track:

As we know the speed and remaining distance

Speed=\frac{distance}{time}\\8=\frac{4}{time}\\ time=\frac{4}{8}\\time=0.5\ hours

Masha needs 0.5 hour to complete the track ..

7 0
3 years ago
Read 2 more answers
Which point, (5/2, 3) or (3/2, 20), is on the graph of 2x - 2/3y =3?<br><br> show steps pls!
Anna11 [10]
You should try both points
put  x=5/2 and y=3
5-2=3
the first one is on the graph
put  x=3/2 and y=20
3-40/3≠3
the second one is not on the graph


4 0
4 years ago
Which expression is equivalent to 10√5<br>A. √500<br>B.√105<br>C.√50<br>D.√15
julsineya [31]
50 is the answer to this question
3 0
3 years ago
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