Question

[infinity] n = 1 3n + 14−n Determine whether the geometric series is convergent or divergent. Justify your answer. Converges; the series is a constant multiple of a geometric series. Converges; the limit of the terms, an, is 0 as n goes to infinity. Diverges; the limit of the terms, an, is not 0 as n goes to infinity. Diverges; the series is a constant multiple of the harmonic series. If it is convergent, find the sum. (If the quantity diverges, enter DIVERGES.)

Answer 1

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Answer 2

Answer:

n = 14/11

Step-by-step explanation:

n =13n +14 - n

=12n + 14

n - 12n=14

-11n = 14

divide both sides by - 11

i think