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4 years ago

13

The length of a rectangle is increasing at a rate of 4 cm/s and its width is increasing at a rate of 5 cm/s. when the length is

14 cm and the width is 9 cm, how fast is the area of the rectangle increasing?

1 answer:

Zepler [3.9K]4 years ago

8 0

To be honest i really dont know sorry

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Given two points M & N on the coordinate plane, find the slope of MN , and state the slope of the line perpendicular to MN .

telo118 [61]

Answer:

Problem 1) $m = \dfrac{1}{4}$ $slope_{perpendicular} = -4$

Problem 2) $m = \dfrac{1}{3}$ $slope_{perpendicular} = -3$

Step-by-step explanation:

$slope = m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$slope_{perpendicular} = \dfrac{-1}{m}$

Problem 1) M(9,6), N(1,4)

$slope = m = \dfrac{6 - 4}{9 - 1} = \dfrac{2}{8} = \dfrac{1}{4}$

$slope_{perpendicular} = \dfrac{-1}{\frac{1}{4}} = -4$

Problem 2) M(-2,2), N(4,-4)

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$slope_{perpendicular} = \dfrac{-1}{\frac{1}{3}} = -3$

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3 years ago

What do the following two equations represent?

aleksandr82 [10.1K]

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3 years ago

The probability density function f(x) for a uniform random variable x defined over the interval [2, 10] is

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F(x) = {1/8, 2 ≤ x ≤ 10}

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3 years ago

Y=-3/2x+9 2x+2y=16 how to solve it by using substitution

ycow [4]

Equation 1) y = -3/2x + 9
Equation 2) 2x + 2y = 16

Add 3/2x to both sides of equation 1.

1) 3/2x + y = 9

Then, multiply all of equation one by 2.

1) 2(3/2x + y = 9)

1) 3x + 2y = 18
2) 2x + 2y = 16

Subtract.

x = 2

Plug in 2 for x in the first equation.

y=-3/2x+9

y = -3/2(2) + 9

y = -3 + 9

y = 6

So, x=2 and y = 6

~Hope I helped!~

3 0

3 years ago

Read 2 more answers

Please Help ASAP

Tju [1.3M]

9514 1404 393

Answer:

no solution

Step-by-step explanation:

The discriminant is ...

b^2 -4ac = (-4)^2 -4(2)(16) = 16 -128 = -112

A negative discriminant means there are no real solutions to the equation.

_____

The complex solutions are 1±i√7.

If we assume the equation has a typographical error and is intended to be ...

2x^2 -4x -16 = 0

The solutions are x = -2 and x = 4.

3 0

3 years ago