Question

a rectangular prism measures 8 inches in width, 12 inches in length, and 4 inches in height. what is the surface area of the prism?

Answer 1

For this case we have that the surface area of the prism is given by:

$SA = A_ {l} + 2B$

Where:

$A_{l}$: Is the lateral area

B: It is the area of the base

$A_ {l} = P.h$

Where:

Q: It is the perimeter of the base

h: It's the height

$A_ {l} = 40 * 4\\A_ {l} = 160 \ in ^ 2$

On the other hand:

$B = 12 * 8\\B = 96 \ in ^ 2$

So, we have:

$SA = A_ {l} + 2B\\SA = 160 \ in ^ 2 + 2 * 96 \ in ^ 2\\SA = 352 \ in ^ 2$

Answer:

$SA = 352 \ in ^ 2$

Answer 2

Answer:

The surface area of prism = 352 square inches

Step-by-step explanation:

Formula:-

Surface are of rectangular prism = 2(lb + bh + lh)

l - Length of prism

b - width of prism

h - Height of prism

It is given that,a rectangular prism measures 8 inches in width, 12 inches in length, and 4 inches in height.

To find the surface area of prism

l = 12 inches

b = 8 inches

h = 4 inches

surface area =  2(lb + bh + lh) = 2(12*8 + 8*4 +12*4)

  = 2(96 + 32 + 48) = 352 square inches.

Therefore the surface area of prism = 352 square inches