Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit: 
There are 4 digits that we can choose from. (3, 4, 6, and 7) 
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options. 
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third. 
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
 
        
             
        
        
        
Answer:
4
Step-by-step explanation:
4 - 2 = 4 + -2 = -2 + 4
 
        
             
        
        
        
The sum of these numbers is an even number and it is prime. 
Therefore it is not an odd number and is not a composite number.
        
             
        
        
        
Y=6. you would replace x with 7 in the equation. 
6(7) = 7y
42=7y
6=y
        
             
        
        
        
Answer:
it's d
Step-by-step explanation:
because the answer would be the same on both sides