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Ahat [919]
4 years ago
8

In Exercise, expand the logarithmic expression. ln x/x + 1

Mathematics
1 answer:
kotegsom [21]4 years ago
6 0

Answer:

In x^2-x/x^2-1

Step-by-step explanation:

In x/x+1 = In x/x+1 × x-1/x-1 = In x(x-1)/(x+1)(x-1) = In x^2-x/x^2-1

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AYO HELP PLEASE THANK YOU
enyata [817]

Answer:

60

Step-by-step explanation:

60* of the circumference would be 60-the total circumference.

5 0
3 years ago
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An image of a parabolic lens is projected onto a graph. The y-intercept of the graph is (0, 90), and the zeros are 5 and 9. Whic
seraphim [82]
Given:

y-intercept of the graph: (0, 90)
zeros: 5 and 9

The equation that models the function based on the zeros given, is either

y = 90 (x-5) (x-9)
or
y= 2(x-5)(x-9)

try solving for the y-intercept of each function, 

y = 90 (0-5) (0-9)
  y = 4050
(0, 4050)

y = 2(0-5) (0-9)
y = 90
(0, 90)

therefore, the equation that models the function is y = 2(x-5)(x-9)

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3 years ago
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Answer the question below thx
AnnZ [28]

Answer:

The second option: "Even though Antartica is cold and has snow, it is a desert."

Step-by-step explanation:

This is the answer because by reading the paragraph, you will see that the main idea is stated in the first few sentences.

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3 years ago
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You are seeking to be emancipated from your parents. You are looking for an apartment. There are two final choices. Apartment A
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Answer:

20 months

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Initial difference = 500$

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500 / 25 = 20

4 0
3 years ago
Solve the inequality 3u+3(u+1)>2u+7 and write the solution in interval notation.
strojnjashka [21]

<u>Given</u>:

The given inequality is 3u+3(u+1)>2u+7

We need to determine the solution of the inequality in interval notation.

<u>Solution of the inequality:</u>

The solution of the inequality can be determined by simplifying the inequality.

Thus, we have,

3u+3u+3>2u+7

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Subtracting both sides by 3, we get;

6 u>2 u+4

Subtracting both sides by 2u, we have;

4 u>4

Dividing both sides by 4, we get;

u>1

Writing it in interval notation, we get;

(1, \infty)

Thus, the solution of the inequality is (1, \infty)

5 0
3 years ago
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