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noname [10]
4 years ago
6

Which of the following is th least

Mathematics
1 answer:
Nookie1986 [14]4 years ago
6 0
Which is the least of what!?
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Tell whether each pair of angle measurements are complementary, supplementary, or neither: 67°, 105°
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Step-by-step explanation:

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3 years ago
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When there are few data, we often fall back on personal probability. There had been just 24 space shuttle launches, all successf
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  1

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3 years ago
What is the answer to (a^3-2a^2)-(3a^2-4a^3)
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7 0
4 years ago
Which simplifications of the powers of i are correct?
OleMash [197]

The correct simplifications of powers of i are:

a. i^27=−i

d. i^8=1

e. i^5=i

Step-by-step explanation:

We know that

i^2=-1\\i^3=-i\\i^4=1

We can use the smaller powers of i to solve the larger powers.

a. i^27=−i

i^{27}\\={i^{24}}.i^3\\={i^{4*6}}.-i\\=(i^4)^6.-i\ \ \ \ As\ we\ know\ i^4=1\\=(1)^6.-i\\=1*-i\\=-i

b. i^28=i

i^{28}\\=i^{4*7}\\=(i^4)^7\\=(1)^7\\=1

c. i^14=1

i^{14}\\=i^{12}.i^2\\=(i^{4*3}).i^2\\=> i^2=-1\\=(i^4)^3.-1\\=(1)^3*-1\\=-1

d. i^8=1

i^8\\=i^{4*2}\\=(i^4)^2\\=(1)^2\\=1

e. i^5=i

i^5\\=i^{2*2*1}\\=i^2*i^2*i\\=(-1)(-1)(i)\\=i

Hence,

The correct simplifications of powers of i are:

a. i^27=−i

d. i^8=1

e. i^5=i

Keywords: Imaginary units, Iota

Learn more about imaginary units at:

  • brainly.com/question/8806598
  • brainly.com/question/8805387

#LearnwithBrainly

6 0
3 years ago
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