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3 years ago

Are the pair of lines parallel, perpendicular or neither? 8x-4y=12 and 4x-y=-15

Mathematics

1 answer:

Orlov [11]3 years ago

6 0

Answer:

neither, would technically be intersecting lines tho

Step-by-step explanation:

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Find the exact solution of x 3x^2+7=28 A.+√7 B.7 C.+7 D.-7

yulyashka [42]

Answer:

x = ± $\sqrt{7}$

Step-by-step explanation:

3x² + 7 = 28 ( subtract 7 from both sides )

3x² = 21 ( divide both sides by 3 )

x² = 7 ( take square root of both sides )

x = ± $\sqrt{7}$

that is x = - $\sqrt{7}$ , x = $\sqrt{7}$

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2 years ago

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Convert to slope intercept form. y + 6 = 4/5 (x + 3)

xenn [34]

X = 5y + 30/4 - 3 is the answer.

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3 years ago

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3. Sally is going to invest $1000 in a CD that

Nikitich [7]

Here you go, you’ll probably have to re-word it for your answer but that was the simplest way to answer it for me.

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3 years ago

The Miguel traces a circle with the radius of 25 cm like the one shown. He will color the shade section what is the area of the

Scilla [17]

Answer: The area of shaded section is 491.07 cm²

Step-by-step explanation:

Given: Radius of the circle = 25 cm

Now as shown in figure the shaded region is a quadrant.

Therefore the central angle is 90°

Now as we know

Area of sector is given by

$Area= \pi r^2 \dfrac{\theta}{360^\circ}$ where r is radius and $\theta$ is central angle

So we have

$Area = \dfrac{22}{7} \times (25)^2\times \dfrac{90^\circ}{360^\circ} \\\\\Rightarrow Area= \dfrac{22}{7} \times 625 \times \dfrac{1}{4} \\\\\Rightarrow Area= \dfrac{11}{7} \times 625 \times \dfrac{1}{2} = 491.07cm^2$

Hence, the area of shaded section is 491.07 cm²

5 0

3 years ago

The perimeter of a regular hexagon is 6x + 30. What is the length of each side of the hexagon?

Fofino [41]

Answer:

x + 5

Step-by-step explanation:

This is actually rather simple to figure out. Simply divide 6x + 30 by 6. That should get x + 5 for the length of one side.

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3 years ago