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natulia [17]
3 years ago
12

Type the correct answer in each box. Spell all the words correctly, and use numerals instead of words for numbers. If necessary,

use / for the fraction bar(s). We can show that ∆ABC is congruent to ∆A′B′C′ by a translation of unit(s) and a across the -axis. Reset Next
Mathematics
1 answer:
Morgarella [4.7K]3 years ago
7 0

Answer:

We can show that ∆ABC is congruent to ∆A′B′C′ by a translation of (x-2, y) unit(s) and a across the x-axis.

Step-by-step explanation:

The triangle ABC is shown in the image attached. The coordinates of the triangle are A(8, 8), B(10, 4), C(2, 6), while the triangle A'B'C' is at A'(6, -8), B'(8, -4), C'(0, -6).

A transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, translation, dilation and rotation.

If a point O(x, y) is translated a units on the x axis and b units on the y axis, the new coordinate is O'(x+a, y+b).

If a point O(x, y) is reflected across the x axis, the new coordinate is O'(x, -y)

Hence if triangle ABC is translated -2 units on the x axis (2 units left), the new coordinates are A*(6, 8), B*(8, 4), C*(0, 6). If a reflection across the x axis is then done, the new coordinates are A'(6, -8), B'(8, -4), C'(0, -6).

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