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4 years ago

10

You are shown either nets or top and side view of three dimensional figures. Match the three dimensional figure to the correct v

iews.
cone

cylinder

rectangular prism

sphere

triangular pyramid

1 answer:

vredina [299]4 years ago

4 0

Answer:

1. rectangular prism

2. cylinder

3. cone

4. triangular pyramid

5. sphere

Step-by-step explanation:

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Together, Steve and Tom sold 104 raffle tickets for their school. Steve sold 17 more than twice as many raffle tickets as Tom. H

Svetllana [295]

Tom = x
steve = 2x + 17

x + 2x + 17 would then simplify to 3x + 17

104 = 3x + 17
87 = 3x
29 = x

then substitute x into tom and steve

steve = 75 tickets
tom = 29 tickets

i think...

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4 years ago

What is the slope of the line? Type fractions as y/x).

zvonat [6]

Answer:

Slope is (1, 2)

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3 years ago

Selecting 5 students to participate in a math contest would require the calculating of a permutation or combination?

Maslowich

Selecting 5 students to participate in a math contest would require combinations.

<u>SOLUTION: </u>

given that, Selecting 5 students to participate in a math contest would require the calculating of a permutation or combination?

So, we need to differentiate between permutations and combinations.

Permutations - In mathematics, permutation is the act of arranging the members of a set into a sequence or order

Combinations - In mathematics, a combination is a selection of items from a collection, such that the order of selection does not matter.

So, now, for our math test, we just require students but not in an order nor with arrangements.

Hence, selecting 5 students to participate in a math contest would require combinations.

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3 years ago

Consider the following figure... True or False..

garik1379 [7]

It should be true , hope this helped

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3 years ago

Find the value of X! Please help!

nydimaria [60]

ANSWER

$x = 8 \sqrt{3}$

EXPLANATION

${h}^{2} = {y}^{2} + {4}^{2}$
This implies that,

${h}^{2} = {y}^{2} + 16...eqn1$

Also,

${h}^{2} + {x}^{2} = {16}^{2} ...eqn2$

And

${y}^{2} + {12}^{2} = {x}^{2}$

${y}^{2}={x}^{2} - 144 ...eqn3$

Put equation 1 into equation 2.

This will give us,

${y}^{2} + 16 + {x}^{2} = {16}^{2}$

${y}^{2} +{x}^{2} = {16}^{2} - 16$

${y}^{2} +{x}^{2} =16 ( 16 - 1)$

${y}^{2} +{x}^{2} =240...eqn4$

We put equation 3 into equation 4,

${x}^{2} - 144+{x}^{2} =240$

We simplify to get,

$2 {x}^{2} = 384$

${x}^{2} = 192$

$x = \sqrt{192}$

$x = 8 \sqrt{3}$

4 0

3 years ago