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Ira Lisetskai [31]
3 years ago
11

Is 15 a perfect square​

Mathematics
2 answers:
yulyashka [42]3 years ago
5 0
No its not. the square root of 15 is about 3.873. Thus, the square root of 15 is not an integer, and therefore 15 is not a square number.
kogti [31]3 years ago
3 0

Answer:

No.

Step-by-step explanation:

No.

16 is a perfect square because 4 times itself is 16.

9 is a perfect square because 3 times itself is 9.

So there are no whole numbers such that when yoy square it (times it by itself) gives you 15.

Whole numbers are numbers contained within the following set:

{0,1,2,3,4,5,...}

So here are the first few perfect squares:

0 because 0(0)=0

1 because 1(1)=1.

4 because 2(2)=4.

9 because 3(3)=9.

16 because 4(4)=16.

25 because 5(5)=25.

36 because 6(6)=36.

49 because 7(7)=49.

64 because 8(8)=64.

81 because 9(9)=81.

As you can see 15 isn't in that list.

You might be interested in
Which equation does this image represent?
nirvana33 [79]

Given:

Image of the ellipse

To find:

The equation of the image

Solution:

The given image is a ellipse.

Center of the ellipse = (0, 0)

x-axis points are (-3, 0) and (3, 0).

y-axis points are (2, 0) and (-2, 0).

Standard form of equation of ellipse:

$\frac{(x-h)^{2}}{a^{2}}+\frac{(y-k)^{2}}{b^{2}}=1

where (h, k) is the center = (0,0)

a is the point on x-axis where y = 0. Hence a = 3.

b is the point on y-axis where x = 0. Hence b = 2.

Substitute this in the standard form of ellipse.

$\frac{(x-0)^{2}}{3^{2}}+\frac{(y-0)^{2}}{2^{2}}=1

$\frac{x^{2}}{9}+\frac{y^{2}}{4}=1

To make the denominator same multiply 1st term by \frac{4}{4} and 2nd term by \frac{9}{9}.

$\frac{4x^{2}}{4\times9}+\frac{9y^{2}}{9\times4}=1

$\frac{4x^{2}}{36}+\frac{9y^{2}}{36}=1

$\frac{4x^{2}+9y^{2}}{36}=1

Multiply by 36 on both sides

$\frac{4x^{2}+9y^{2}}{36}\times 36=1\times 36

${4x^{2}+9y^{2}}={36}

The equation of the image is ${4x^{2}+9y^{2}}={36}.

8 0
4 years ago
1.) The commuter trains on the Red Line for the Regional Transit Authority (RTA) in Cleveland, OH, have a waiting time during pe
alisha [4.7K]

Answer:

a) For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:

X \sim Unif(a=0,b=8)

Where a and b represent the limits of the distribution.

b) f(x) = \frac{1}{8}= 0.125, a\leq x \leq b

And the height for this case would be 0.125

Step-by-step explanation:

Part a

For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:

X \sim Unif(a=0,b=8)

Where a and b represent the limits of the distribution.

Part b

For this case the density function would be given by:

f(x) = \frac{1}{8}= 0.125, a\leq x \leq b

And the height for this case would be 0.125

And f(x)= 0  for other case.

The cumulative distribution function would be given by:

F(x) = 0, x

F(x) = \frac{x-a}{b-a}= \frac{x}{8}, 0\leq x < 8

F(x) = 1, x\geq 8

3 0
3 years ago
the sum of two numbers is 63. one ninth of the first number plus one sixth of the second number is 21. find the numbers
PSYCHO15rus [73]

Answer: x= -189, y =252

Step-by-step explanation:

Let the first number be x and second number be y

so

x + y = 63

x = 63-y

now

1/9 of x + 1/6 of y = 21

x/9 + y/6 = 21

substituting x's value from equation i

(63-y)/9 + y/6 = 21

(378-6y+9y)/54 = 21

378+3y = 1134

3y = 1134-378

so, 3y = 756

so, y = 756/3

so, y = 252

now

x = 63-252

so, x = -189

6 0
3 years ago
Solve the equation. 123 123
ahrayia [7]

Answer:

1isanswer

Step-by-step explanation:

yyyyyyyyggg

6 0
2 years ago
What is 2 to the 3rd power multiply by 10 subtract 8 + 3.5 to the second power​
alex41 [277]

Answer:

84.25

Step-by-step explanation:

first do the powers 2 to the 3rd power 8 3.5 to the second power 12.25 8 x 10 80 - 8 = 72 + 12.25 = 84.25

3 0
3 years ago
Read 2 more answers
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