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Alex73 [517]
3 years ago
10

3/4m^2-1 -5/2m+1 what is the answer and the solution

Mathematics
1 answer:
Ratling [72]3 years ago
5 0
Solve Using the Quadratic Formula (m+ 4)(4m-2)=5(m+3)-10 ..... Use the quadratic formula to find the solutions.
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Answer:

D) log_2(x)+3log_2(9)

Step-by-step explanation:

Given: log_2(9x^{3})

Use Exponent Rule: 3log_2(9x)

Use Addition Rule: log_2(x)+3log_2(9)

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Step-by-step explanation:

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2 years ago
Calculate the effective annual interest rate if the annual interest rate, i, is 9%.
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2 years ago
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an open rectangular cardboard box with a square base is to have a volume of 256cm^3. Find the dimensions of the box if the area
Anit [1.1K]
Let
x------> the length side of the square base of the box
y-------> the height of the box

we know that
volume of the box=b²*h
b=x
h=y
volume=256 cm³
so
256=x²*y------>y=256/x²-------->  equation 1

<span>The amount of material used is directly proportional to the surface area, so we will minimize the amount of material by minimizing the surface area.</span>

surface area of the cardboard=area of the base+perimeter of base*height
area of the base=x²
perimeter of the base=4*x
height=y
surface area=x²+4x*y-----> equation 2
substitute equation 1 in equation 2
SA=x²+4x*[256/x²]-----> SA=x²+1024/x

step 1 
find the first derivative of SA and equate to zero
2x+1024*(-1)/x²=0------> 2x=1024/x²----> x³=512--------> x=8 cm
y=256/x²------> y=256/8²-----> y=4 cm

the answer is
the length side of the square base of the box is 8 cm
the height of the box is 4 cm

5 0
2 years ago
The high school leadership team is having a car wash. They charge $5.50 for large cars and $4.00 for small cars . They had a suc
11Alexandr11 [23.1K]

Answer: 56 large cars and 86 small cars.

Step-by-step explanation:

Let's call:

l: the number of large cars.

s: the number of small cars.

Then, you can set up the following system of equations:

\left \{ {{l+s=142} \atop {5.50l+4.0s=652.50}} \right.

You can use the Elimination Method:

- Multiply the first equation by -4.0

- Add both equations.

- Solve for l.

\left \{ {{-4.0l-4.0s=-568} \atop {5.50l+4.0s=652.50}} \right.\\--------\\1.5l=84.5

l≈56

Substitute l=56 into one of the original equations and solve for <em>s:</em>

<em> </em>56+s=142\\s=142-56\\s=86

3 0
2 years ago
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