Answer:
-68/7
Step-by-step explanation:
slope1 of Car 1 that pass (-5,-8) (2,7)
= (y1-y2)/(x1-x2)=(2-(-5))/(7-(-8))=7/15
Slope2 of car 2 that pass (5,1) (10,y)
slope 1 and slope2 are perpendicular =>slope 2 =-15/7
make slope2 y=(-15/7)x+b
for it pass(5,1) => 1=(-15/7)5+b =>b=82/7 => y=(-15/7)x+82/7
put (10,y) in => y=(-15/7) 10+82/7=-68/7
Step 1: Factor both the numerator and denominator of the fraction. Step 2: Reduce the fraction. Step 3: Rewrite any remaining expressions in the numerator and denominator. Step 1: Factor both the numerator and denominator of the fraction.
6=2 no solution
first multiple the number in the left side
than subtract
than you will get 6=2 no solution
Answer:
easyyyyyyy
Step-by-step explanation:
table J!
The equation between the number of days remaining and number of hours is given as y= -5x+50.
<h3>How to illustrate the equation?</h3>
Let y be the number of days remaining and x be the no.of hours.
From the graph the slope of the line is given by m.
m=(y2 - y1)/(x2 - x1)
m=(30 - 40)/(4 - 2)
m= -10/2 = -5.
The above slope is in between points 2 and 4. As the line has a constant rate of growth the slope is the same between any points of the line.
Therefore the equation between the no.of days remaining and no.of hours is given by
y=mx +c.
y=-5x+c
Now to find the value of c. This can be determined by substituting the x and y values at a particular instant. For x=0,y=50. Therefore by these values, we get,
50= -5(0)+c
c=50.
Therefore the relation between the number of days remaining and number of hours is given as y= -5x+50.
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