Answer:
π
Step-by-step explanation:
Solve for x on the interval [0, 2pi]
Given the equation
Sinx = cosx + 1
Square both sides of the equation
Sin²x = (cos x + 1)²
Sin²x = cos²x + 2cos x + 1
Since Sin²x = 1 - cos²x
1 - cos²x = cos²x + 2cos x + 1
Collect like terms
1-1-cos²x-cos²x-2cos x = 0
-2cos²x-2cos x = 0
-2cos²x = 2cos x
-cosx = 1
cos x = -1
x = arccos -1
x = 180 degrees
<em>Hence the value of x = π</em>
X=lenght of the shortest side
15 in / 8 in=9 in / x
15 in * x=9 in * 8 in
x=(9 in * 8 in) / 15 in=72 in² / 15 in=4.8 in
Answer: C) 4.8 inches.
3A^2 dA/dt + 3B^2 dB/dt = 0
If A=2, then 8+B^3=9, B=1
12 dA/dt + 9 = 0
dA/dt = -3/4
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Collect like terms


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Nine on the left side then 5 on the top