All categories

3 years ago

1.What is the core characteristic that defines a zero-based budget?

Mathematics

1 answer:

lakkis [162]3 years ago

7 0

Answer:

1. You account for every dollar you make to where your budget shows you have $0

2. She will have $125 leftover to budget out as she sees fit

3. If she does not account for it she may over spend or think she has extra money

4. I would put it in savings

5. No this is not what it means. This means that your paycheck will be able to cover your expenses.

6. You should put extra money in savings. You never know what will occur and savings can always help.

Step-by-step explanation:

You might be interested in

How I poop and fart jdkdksmrjddj

PilotLPTM [1.2K]

So you gonna.. it comes out from your but ( fat is a very polite action, recommend to do in the crowded place - Poup is an action that make we fell sastified, make people happy either) Good luck !

Hope it helps! If it is, Brainliest please!

4 0

2 years ago

Find m<br> …………….. ………….. …………..

xz_007 [3.2K]

Answer:

Hope this helps I'm not sure if its correct though, it must be correct anyway. So yea.

7 0

2 years ago

The nth term of a sequence is represented by 3n4−10/6n4+7 . What is the limit of the the nth term as n becomes increasingly larg

Cerrena [4.2K]

Answer:

Step-by-step explanation:

Given the limit of the function expressed as;

$\lim_{n \to \infty} \frac{3n^4-10}{6n^4+7} \\$

To take the limit, we nee to divide through by the highest power of n first

$\lim_{n \to \infty} \frac{3n^4/n^4-10/n^2}{6n^4/n^4+7/n^4}\\= \lim_{n \to \infty} \frac{3-10/n^2}{6+7/n^4}\\= \frac{3-10/(\infty)^2}{6+7/(\infty)^4}\\= \frac{3-0}{6-0}\\= \frac{3}{6}\\ = \frac{1}{2}\\$

Hence the limit of the the nth term as n becomes increasingly large is 1/2

3 0

2 years ago

Find the distance that the points is given on the graph ?

EleoNora [17]

From the graph, the given points are (2,-1) and (4,0). Use the distance between two points formula:

$\large \boxed{ \sqrt{ {(x_2 - x_1)}^{2} + {(y_2 - y_1)}^{2} } }$

Substitute these points in the formula.

$\large{ \sqrt{ {(2 - 4)}^{2} + {( - 1 - 0)}^{2} } } \\ \large{ \sqrt{ {( - 2)}^{2} + {( - 1)}^{2} } } \\ \large{ \sqrt{4 + 1} \longrightarrow \sqrt{5} }$

Hence, the distance is √5

Answer

√5

7 0

3 years ago

Answer the question :)

inn [45]

Answer:

A. -11

Step-by-step explanation:

In the function, replace x with -2

R(x) = x^2 - 3x - 1 ➡ R(-2) = (-2)^2 - 3 × 2 -1 = -11

5 0

3 years ago