<span>If tan theta= 15/8, then theta is expected that theta is found in the first and third quadrant. the y-component is 15 and the x-component is 8. hence the hypotenuse is 17 from the pythagoren theorem. cos theta thus is equal to 8/17, sec theta is equal to 17/8. csc theta is equal to 17/15. answer are A and D</span>
Answer:
Angle 5 = 122
Step-by-step explanation:
Assume EB and AD intersect each other at point C
As this is the circle, four points A,B,D,E are all on the circle, so that we have:
+) m∠EBD = 1/2 measure of arc ED (small arc)
=> m∠EBD = 1/2 . 66 = 33 degree
=> m∠CBD = 33
+) m∠ADB = 1/2 measure of arc AB (small arc)
=>m∠ADB = 1/2 . 50 = 25 degree
=>m∠CDB = 25 degree
In the triangle CDB, we have total measure of three internal angles is 180 degree
=> Angle 5 + m∠CDB + m∠CBD = 180
=> Angle 5 + 25 + 33 = 180
=> Angle 5 = 180 -25 - 33 = 122 degree
Answer:
∠BAD=20°20'
∠ADB=34°90'
Step-by-step explanation:
AB is tangent to the circle k(O), then AB⊥BO. If the measure of arc BD is 110°20', then central angle ∠BOD=110°20'.
Consider isosceles triangle BOD (BO=OD=radius of the circle). Angles adjacent to the base BD are equal, so ∠DBO=∠BDO. The sum of all triangle's angles is 180°, thus
∠BOD+∠BDO+∠DBO=180°
∠BDO+∠DBO=180°-110°20'=69°80'
∠BDO=∠DBO=34°90'
So ∠ADB=34°90'
Angles BOD and BOA are supplementary (add up to 180°), so
∠BOA=180°-110°20'=69°80'
In right triangle ABO,
∠ABO+∠BOA+∠OAB=180°
90°+69°80'+∠OAB=180°
∠OAB=180°-90°-69°80'
∠OAB=20°20'
So, ∠BAD=20°20'
Answer:
We are told of a 90 degree angle. plus we are told that GH and HI are similar.
Hence: Angle I is = 45 degree or Option C
29/92 you minus sixty three by ninety two to get the probability of the event not to occur.
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