<img src="https://tex.z-dn.net/?f=3m%20%2B%204%20%3D%201" id="TexFormula1" title="3m + 4 = 1" alt="3m + 4 = 1" align="absmiddle"

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Verizon [17]

3 years ago

class="latex-formula">
Help for math hw

Mathematics

2 answers:

vlada-n [284]3 years ago

5 0

First move the constant to the right and change its sign to the opposite,
3m=1-4

Then calculate,
3m=-3

Then divide both sides of the equation by 3,
m=-1

So the answer is m=-1

Rashid [163]3 years ago

3 0

The answer to this question is -1

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The endpoints of segment RS are R(-4, 3) and S(8, -5). Complete each statement using a fraction.

Ray Of Light [21]

Answer:

a. (-1 , 1) is the point at 1 : 3 of the way from R to S

b. (5 , -3) is the point at 3 : 1 of the way from R to S

Step-by-step explanation:

* Lets explain how to solve the problem

- If point (x , y) divide a line segment whose end points are

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ , at ratio

$m_{1}:m_{2}$ from the first point, then

$x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$ and

$y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

* Lets solve the problem

∵ RS is a line segment whose end points are R (-4 , 3) and S (8 , -5)

∵ Point (-1 , 1) divides it at ratio $m_{1}:m_{2}$ from R

- By using the rule above

∴ $-1=\frac{-4m_{2}+8m_{1}}{m_{1}+m_{2}}$

- By using cross multiplication

∴ $(-1)m_{1}+(-1)m_{2}$ = $-4m_{2}+8m_{1}$

- By collecting $m_{1}$ in one side and $m_{2}$ in the

other side

∴ $3m_{2}=9m_{1}$

- Divide both sides by 3

∴ $m_{2}=3m_{1}$

∴ $m_{1}=\frac{1}{3}m_{2}$

∴ (-1 , 1) is the point at 1 : 3 of the way from R to S

∵ RS is a line segment whose end points are R (-4 , 3) and S (8 , -5)

∵ Point (5 , -3) divides it at ratio $m_{1}:m_{2}$ from R

- By using the rule above

∴ $5=\frac{-4m_{2}+8m_{1}}{m_{1}+m_{2}}$

- By using cross multiplication

∴ $5m_{1}+5m_{2}$ = $-4m_{2}+8m_{1}$

- By collecting $m_{1}$ in one side and $m_{2}$ in the

other side

∴ $9m_{2}=3m_{1}$

- Divide both sides by 3

∴ $3m_{2}=m_{1}$

∴ $\frac{m_{1}}{m_{2}}=3$

∴ (5 , -3) is the point at 3 : 1 of the way from R to S

8 0

4 years ago

Here's another problem plz answer this correct 10 points and brainly!<br><br> NO LINKS NO SCAM LINKS

Dafna11 [192]

Lolz i don’t know I just want points:)

8 0

3 years ago

Read 2 more answers

If integer k is equal to the sum of all even multiples of 15 between 295 and 615, what is the greatest prime factor of k?

ohaa [14]

Answer:

The greatest prime factor of k is 11.

Step-by-step explanation:

∵ LCM( 2, 15) = 30,

Thus, the even multiple of 15 must be multiple of 30,

That is, the even multiple of 15 between 295 and 615 are

300, 330, 360,..........600

Which is an AP,

Having first term, a = 300,

Common difference, d = 30,

If n be the number terms,

Last term = $a+(n-1)d$

$=300+(n-1)30$

$=270 + 30n$

$\implies 270+30n = 600\implies 30n = 330\implies n = 11$

Hence, the sum of the all even multiple of 15 from 295 to 615,

$S_{11}=\frac{11}{2}(2(300)+(11-1)30)=\frac{11}{2}(600+300)=\frac{11}{2}(900)=11\times 450$

According to the question,

$S_{11}=k$

⇒ k = 11 × 450 = 11 × 5 × 5 × 3 × 3 × 2

Hence, the greatest prime factor of k is 11.

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3 years ago

The Smiths family had dinner at their favorite restaurant. A 8% sales tax was added to their bill. Amy paid the bill with a $30

Otrada [13]

I believe the answer is $63.32 before tax.

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An item is regularly priced at $95 . it is on sale for 40% off the regular price. how much (in dollars) is discounted from the r

sergiy2304 [10]

95.00*40%=
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3 years ago