Answer:
Step-by-step explanation:
2q + 2p = 1 + 5q
-3q + 2p = 1
-3q = 1 - 2p
3q = 2p - 1
q = (2p -1)/3
Answer:
Option (c) is correct.
Step-by-step explanation:
Given equation is :
The equation can be solved for a as follows :
Step 1.
Cross multiply the given equation
Step 2.
Now subtract b on both sides
3s-b = a+b+c-b
3s-b = a+c
Step 3.
Subtract c on both sides
3s-b-c=a+c-c
⇒ a=3s-b-c
The statement that is true for Darpana is " In step 3, she needed to subtract c rather than divide".
Step-by-step explanation:
Add 44 to both sides.
2x=10+4
2x=10+4
2 Simplify 10+410+4 to 1414.
2x=14
2x=14
3 Divide both sides by 22.
x=\frac{14}{2}
x=
2
14
4 Simplify \frac{14}{2}
2
14
to 77.
x=7
x=7
Done
9514 1404 393
Answer:
100°
Step-by-step explanation:
The relevant relation for angle x is ...
x = (AB +DE)/2
and for angle y, it is ...
y =(AC -DE)/2
Using the second relation to write an expression for DE, we have ...
DE = AC -2y
In the first equation, this lets us write ...
x = (AB +(AC -2y))/2 = (AB +(2AB -2y))/2
2x = 3AB-2y . . . . . . . . . . . . . . multiply by 2
(2x +2y)/3 = AB = AC/2 . . . . . add 2y; divide by 3
AC = (4/3)(x +y) = (4/3)(60° +15°) . . . . multiply by 2, substitute known values
AC = 100°
Answer:
The length of SO is 46 units
Step-by-step explanation:
<em>In a parallelogram, </em><em>diagonals bisect each other,</em><em> which means meet each other in their mid-point</em>
∵ SNOW is a parallelogram
∵ SO and NW are diagonals
∵ SO ∩ NW at point D
→ That means D is the mid-point of SO and NW
∴ D is the mid-point of SO and NW
∵ D is the mid-point of SO
→ That means D divide SO into two equal parts SD and DO
∴ SD = DO
∵ SD = 9x + 5
∵ DO = 13x - 3
→ Equate them
∴ 13x - 3 = 9x + 5
→ Subtract 9x from both sides
∵ 13x - 9x - 3 = 9x - 9x + 5
∴ 4x - 3 = 5
→ Add 3 to both sides
∵ 4x - 3 + 3 = 5 + 3
∴ 4x = 8
→ Divide both sides by 4
∴ x = 2
→ To find the length of SO substitute the value os x in SD and DO
∵ SO = SD + DO
∵ SD = 9(2) + 5 = 18 + 5 = 23
∵ DO = 13(2) - 3 = 26 - 3 = 23
∴ SO = 23 + 23 = 46
∴ The length of SO is 46 units
