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Rina8888 [55]
3 years ago
10

Which operations would create an equivalent system of equations with opposite like terms?

Mathematics
2 answers:
Bumek [7]3 years ago
7 0

Answer:the first equation can be multiplied by 5 and the second equation by 3

Step-by-step explanation:

fredd [130]3 years ago
7 0

Answer: A

Step-by-step explanation:

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Please help me <br> 3(x + 2) * 10 * 7 divided by 70 - 2 (x+2)<br><br> Simplify
I am Lyosha [343]

Answer:

= 105(x+2)/33-x

Step-by-step explanation:

Given the expression

[3(x+2)*10*7]÷70 - 2(x+2)

= 3(x+2)*70÷70 - 2(x+2)

= 210(x+2)/70-2x-4

= 210(x+2)/66-2x

= 210(x+2)/2(33-x)

= 105(x+2)/33-x

8 0
2 years ago
Consider the quadratic equation below. 4x^2-5=3x+4 Determine the correct set-up for solving the equation using the quadratic for
Kipish [7]
4x²-5=3x+4
4x²-3x-9=0

x=(3±√((-3)²-4*4*-9))/2*4

x=3±√(9+144) /8

x=(3±√153) /8

x=⅜±√153/8
4 0
2 years ago
? Don't Send links, don't Write random things and get the points for free.
alekssr [168]

Answer:

V = 1847.26\ ft^3

Step-by-step explanation:

Step 1:  Determine the volume

V=\pi r^2h

V = \pi *(7\ ft)^2 * (12\ ft)

V = \pi *49\ ft^2 * 12\ ft

V = \pi  * 588\ ft^3

V = 1847.26\ ft^3

Answer:   V = 1847.26\ ft^3

6 0
2 years ago
an isosceles triangle has congruent sides of 20cm. the base is 10cm. find the height of the triangle.​
dolphi86 [110]

Answer:

\large\boxed{A_\triangle=25\sqrt{15}\ cm^2}

Step-by-step explanation:

Look at the picture.

The formula of an area of a triangle:

A_\triangle=\dfrac{bh}{2}

<em>b</em><em> - base</em>

<em>h</em><em> - height</em>

<em />

We need a length of a height.

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have:

leg=5,\ leg=h,\ hypotenuse=20

Substitute:

5^2+h^2=20^2

25+h^2=400             <em>subtract 25 from both sides</em>

h^2=375\to h=\sqrt{375}\\\\h=\sqrt{(25)(15)}\\\\h=\sqrt{25}\cdot\sqrt{15}\\\\h=5\sqrt{15}\ cm

Calculate the area:

A_\triangle=\dfrac{(10)(5\sqrt{15})}{2}=\dfrac{50\sqrt{15}}{2}=25\sqrt{15}\ cm^2

8 0
3 years ago
One frame of a film in a projector is about 50 mm high. The film isOne frame of a film in a projector is about 50 mm high. The f
OlgaM077 [116]
The frame of film is actually 50 mm high, but it looks 16 m high on the screen.

Remember that 1 m = 1,000 mm.

So everything looks (16,000)/(50) = <u>320 times</u> as big on the screen
as it is on the film. That's called the scale factor.

The penguin is 35 mm high on the film. He'll look 320 times bigger on the screen.

(320) x (35 mm) = 11,200 mm = <u>11.2 meters</u> high
4 0
3 years ago
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