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Nonamiya [84]
3 years ago
8

Which of the following measurements is the smallest?

Mathematics
1 answer:
kirza4 [7]3 years ago
8 0
It's millimeter. the smallest measurement among them.
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Customers of a phone company can choose between two service plans for long distance calls. The first plan has no monthly fee but
larisa [96]

0.17x = 0.12x +18

subtract 0.12x from each side

0.05x = 18

divide both sides by 0.05

x = 18/0.05 = 360

 360 minutes would be the answer



Please mark brainliest


7 0
3 years ago
Read 2 more answers
I need so much help please somebody help me
marysya [2.9K]

Answer:

$448

Step-by-step explanation:

You need to find 2% of 400.00, so you would do this: 0.02 · 400 = 8

That means $8 is 2% of 400, so all you need to do is multiply 8 by 6 to get 48. Add that number to the original $400, and you get $448.

<em>Hope this answers your question!</em>

6 0
3 years ago
Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha
const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

P(1.83\leq X\leq  a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06

Thus, the value of <em>a</em> is 12.06.

7 0
3 years ago
The average number of tunnel construction projects that take place at any one time in a certain state is 3. Find the probability
slega [8]

Answer: 0.1008188

Step-by-step explanation:

The question will usng the poisson distribution formula:

Given :

Mean(λ) number of occurrence in a given interval = 3

P(X=x) = Probability of exactly x occurrence in a given interval

Number of desired occurence(x) = 5

P(X=x) = [(λ^x) * (e^-λ)] / x!

Where ; e = base of natural logarithm = 2.7182818

P(X=5) = [(3^5) * (e^-3)] / 5!

P(X=5) = [(243) * (0.0497870)] / 120

P(X=5) = [12.098257] / 120

P(X=5) = 0.1008188

6 0
3 years ago
Find three positive consecutive integers such that the product of the smallest and the largest is 17 more than three times the m
trapecia [35]
There are two answers to this question
the first possible answer is 5, 6, and 7 and the second possible answer is -4, -3, and -2


Step-by-step explanation:

let the three numbers be (x-1), x, and (x+1)
the product of the smallest and largest number is 17 more than 3 times the middle number, or
(x-1)(x+1) = 3x+17, or
x^2-1 = 3+17, or
x^2-3x-18 = 0
(x-6)(x+3) = 0
So x = 6 or -3
Then just subtract one and add one to get the other integers. the three numbers are 5, 6, and 7 or -4, -3, and -2
3 0
3 years ago
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