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3 years ago

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Find x value for the point that splits segment co in halt point c is located at 4) and point D is located at (3,7)

1 answer:

VLD [36.1K]3 years ago

8 0

Okay to split a segment in half you just need to find the midpoint of the two endpoints. Mathematically this is just the average of the coordinates of the endpoints which is:

mp=((x1+x2)/2, (y1+y2)/2)

Which in this case is:

mp=((-2+3)/2, (4+7)/2)

mp=(1/2, 11/2)

mp=(0.5, 5.5)

So the x-coordinate by itself is just 0.5, or answer c.

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You borrowed $25 from your friend. You paid him back in full after 6 months. He charged $2 for interest. What was the annual sim

Paraphin [41]

$\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
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P=\textit{original amount}\to& \$25\\
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\end{cases}$

bearing in mind, "t" is in years, 6months is just 1/2 year

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3 years ago

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Evaluate the expression:<br> 9 +7(5-2)<br> Using PEDMAS<br><br> yall i suck at math

ANEK [815]

Hello! :)

Let's use PEMDAS.

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction

(5-2) = 3 Do parenthesis.

7 × 3 = 21 Multiply with what we got after doing the parenthesis.

9 + 21 = 30 Add with what we had left.

30

Hope this helps!

ELITEDIPER

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3 years ago

I can't find area of the triangle

Andreas93 [3]

Answer:

First do the Base multiplied by the Height.

After divide by 2

Step-by-step explanation:

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3 years ago

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Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

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2 years ago

Rafael deposits $5000 into and account that pays simple interest at an annual 5%. He does not make anymore deposits. He makes no

nekit [7.7K]

Answer:

Step-by-step explanation:

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3 years ago

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