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Elina [12.6K]
2 years ago
7

A triangle with sides of 14 15 and 29 does it form a right triangle 

Mathematics
2 answers:
Serhud [2]2 years ago
6 0

Answer:

No

Step-by-step explanation:

Use Pythagorean Theorem: (a^2 + b^2 = c^2)

a^2 + b^2

(14)^2 + (15)^2

196 + 225 = 421

Now for c:

29^2 = 841

841  does not 421 so its not a right triangle

Morgarella [4.7K]2 years ago
3 0

Answer: No.

Step-by-step explanation: This triangle does not form a right triangle because it does not have a 90 degree angle.

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BabaBlast [244]

Answer:

40%

Step-by-step explanation:

3/5x2=6/10

6/10x10=60/100

100-60=40

40%

5 0
3 years ago
30 points!!!!!
dlinn [17]
HELLO...!!

Diagonal = ?
Wide = 20 in.
High = 15 in.

Pythagoras formula: D² = H² + W²

D^2=(15)^2+(20)^2\\ \\D^2=225+400\\ \\D^2=625\\ \\D= \sqrt{625}\\ \\D=25\ in.\quad\Longrightarrow\boxed{\boxed{\mathbb{ANSWER\ \checkmark}}}\\ \\ \\\textbf{HOPE\ THIS\ HELPS...!!}
6 0
2 years ago
The squares of the first five whole numbers​
antiseptic1488 [7]

Answer:

Square each number: 1 , 2 , 3 , 4 , 5:

1² = 1 * 1 = 1

2² = 2 * 2 = 4

3² = 3 * 3 = 9

4² = 4 * 4 = 16

5² = 5 * 5 = 25

~

4 0
3 years ago
What is the length of side a?
Bad White [126]

\huge \bf༆ Answer ༄

According to given figure, The Triangle BDC is a right angled Triangle (Angle D = 90°)

So, we can apply Pythagoras theorem to find the Side a (Hypotenuse)

Now, let's solve ~

  • \sf \: BD {}^{2}   + CD {}^{2} =   BC {}^{2}

  • \sf4 {}^{2}  +  {3}^{2}  =  {a}^{2}

  • \sf16 + 9 =  {a}^{2}

  • \sf \: a {}^{2}  = 25

  • \sf \: a =  \sqrt{25}

  • \sf \: a  = 5 \: units

Therefore, Length of side a is 5 units ~

6 0
2 years ago
I NEED HELP ASAP!!!!!!!!!!
svetoff [14.1K]

Answer:

I know the answer

Step-by-step explanation:

x = random number then y = x + y then x = 68 So we can conclude

5 0
2 years ago
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