All categories

3 years ago

Explain why the equation 5丨x丨-7=7 has only one solution?

Mathematics

2 answers:

Rama09 [41]3 years ago

6 0

The answer to this question that you have me would be 5|x|-7=7 will equal to x=2

romanna [79]3 years ago

4 0

Answer:the answer is

x=±5/14

You might be interested in

It takes the first pipe 9 more hours to fill the pool than the first and the second pipes together and 7 less hours than it woul

Vikki [24]

Let the time taken for the first pipe to fill the pool be x hours
time taken for second pipe to fill the pool is (x+7) hours
time taken for both pipes to fill the pull =(x-9) hours
thus fraction of time taken for both will be written as:
1/(x-9)
thus total fraction for pipe 1 and 2 will be
1/x+1/(x+7)=1/(x-9)
solving for x we get:
x=-3 or x=21
but time is positive, then time taken by first pipe is 21 hours
time taken by both pipes will be 21-9=12 hours

4 0

3 years ago

- Polynomial Functions -For each function, state the vertex; whether the vertex is a maximum or minimum point; the equation of t

vladimir2022 [97]

EXPLANATION

Given the function f(x) = (x-6)^2 + 1

$\mathrm{The\: vertex\: of\: an\: up-down\: facing\: parabola\: of\: the\: form}\: y=ax^2+bx+c\: \mathrm{is}\: x_v=-\frac{b}{2a}$

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

$=x^2-12x+37$ $\mathrm{The\: parabola\: params\: are\colon}$ $a=1,\: b=-12,\: c=37$ $x_v=-\frac{b}{2a}$ $x_v=-\frac{\left(-12\right)}{2\cdot\:1}$ $\mathrm{Simplify}$ $x_v=6$ $y_v=6^2-12\cdot\: 6+37$

Simplify:

$y_v=1$

$\mathrm{Therefore\: the\: parabola\: vertex\: is}$ $\mleft(6,\: 1\mright)$ $\mathrm{If}\: a$ $\mathrm{If}\: a>0,\: \mathrm{then\: the\: vertex\: is\: a\: minimum\: value}$ $a=1$ $\mathrm{Minimum}\mleft(6,\: 1\mright)$ $\mathrm{For\: a\: parabola\: in\: standard\: form}\: y=ax^2+bx+c\: \mathrm{the\: axis\: of\: symmetry\: is\: the\: vertical\: line\: that\: goes\: through\: the\: vertex}\: x=\frac{-b}{2a}$

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

$y=x^2-12x+37$ $\mathrm{Axis\: of\: Symmetry\: for}\: y=ax^2+bx+c\: \mathrm{is}\: x=\frac{-b}{2a}$ $a=1,\: b=-12$ $x=\frac{-\left(-12\right)}{2\cdot\:1}$ $\mathrm{Refine}$

Axis of simmetry : x=6

The quadratic function has the same shape than the parent function y=x^2 because there is NOT a coefficient within x.

3 0

1 year ago

If O is center of circle and angle CBO is 40° then what are values of angle BCO and

Aleksandr [31]

If any line drawn from center of the circle (OC in the diagram) bisect the chord of circle (AB in the diagram), then it is said to be perpendicular to chord AB.
So OC is perpendicular to CB, and we can say that triangle OCB is the Right Triangle.

In the Right Triangle OCB,
angle BCO = 90°
angle COB = 90° - angle CBO = 90° - 40° = 50°

So, option A is the final answer, 90° and 50°.

8 0

3 years ago

Read 2 more answers

PLEASE HELP! HELP!<br> Plot the points (−3, 0) and (3, 5) on the coordinate plane.

iren [92.7K]

(Image below)

Keep in mind that the first number in a coordinate is always on the x-axis (the horizontal line) and the second number is on the y-axis (the vertical line).

If the question asks us to plot (-3, 0), we need to find -3 on the horizontal line and find 0 on the vertical line.

Since 0 means that we go 0 units up, we can just plot the point at -3 on the x-axis.

Next, we need to plot (3, 5). First, let's find the first coordinate by locating 3 on the horizontal axis. Now, we need to find 5 up from that point, because our y-coordinate is 5.

6 0

3 years ago

The first five terms of a sequence are 8, 27, 64, 125, and 216. Which of the following describes how to generate the next term i

oksano4ka [1.4K]

2^3, 3^3,4^3, 5^3, 6^3. The next term in the sequence would be 7^3 which is 343

8 0

4 years ago

Read 2 more answers