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Karolina [17]
3 years ago
11

Compare 5/4 and 9/10 describe two methods you could use to compare the fractions

Mathematics
2 answers:
astraxan [27]3 years ago
8 0
You can use the same denomenators or you can use decimals in order to compare them. I hope this helped!
vredina [299]3 years ago
3 0
By finding the common denominator which is 20  and then what you multiply on the bottom you multiply on the top ; that is one method for adding. :)
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Suppose that appearances of a foe to battle (that is, a random encounter) in a role-playing game occur according to a Poisson pr
Dimas [21]

Answer:

Rate parameter of \mu = 0.5

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:  

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

One appearance per two minutes.

This means that m = 2

Measured in minutes, the time T until the next encounter is Exponential with what rate parameter?

\mu = \frac{1}{m} = \frac{1}{2} = 0.5

So

Rate parameter of \mu = 0.5

5 0
3 years ago
Graph the following inequality and then select the correct graph below. x - y - 2 ≥ 0
-Dominant- [34]

Answer:

the graph in the attached figure

Step-by-step explanation:

we have

x-y-2\geq 0

Isolate the variable y

-y\geq -x+2 -----> Multiply by -1

y\leq x-2

The solution of the inequality is the shaded area below the solid line

The equation of the line is y= x-2

The slope of the line is positive

The y-intercept of the line is the point (0,-2)

The x-intercept of the line is the point (2,0)

Using a graphing tool

the graph in the attached figure

7 0
3 years ago
Read 2 more answers
What is the value of k in the equation?
RSB [31]

Answer:

k=67/1360

Step-by-step explanation: Step 1: Simplify both sides of the equation.

201=4080k

Step 2: Flip the equation.

4080k=201

Step 3: Divide both sides by 4080.

4080k

4080

=

201

4080

k=

67

1360

Answer:

k=

67

1360

3 0
3 years ago
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Natasha2012 [34]
2.28 + 0.449 = 3.319
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3 years ago
Are these angles complementary, supplementary, or neither?
SashulF [63]
I would say complementary because the angle degrees are the same
4 0
3 years ago
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