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7nadin3 [17]
3 years ago
6

What is the maximum value of P = 4x + 2y, given the constraints on x and y listed below? x+2y<_ 10. y<_2. x>_0. y>_0

.

Mathematics
2 answers:
iogann1982 [59]3 years ago
7 0

Answer:

The maximum value of P is 40

Step-by-step explanation:

we have the constraints

x+2y\leq 10 ------> constraint A

y\leq 2 ------> constraint B

x\geq 0 ------> constraint C

y\geq 0 ------> constraint D  

P=4x+2y

Using a graphing tool

The solution of the constraints is the shaded area in the attached figure

For the point (0,0)

The value of P is equal to

P=4(0)+2(0)=0

For the point (6,2)

The value of P is equal to

P=4(6)+2(2)=28

For the point (0,2)

The value of P is equal to

P=4(0)+2(2)=4

For the point (10,0)

The value of P is equal to

P=4(10)+2(0)=40

therefore

The maximum value of P is 40

murzikaleks [220]3 years ago
4 0
The answer is D. 40. I hope this helps!!!!!
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kogti [31]

Answer:

Step-by-step explanation:

10^4 = 10000

1.7 × 10^4 = 1.7 × 10000

= 17000

10^-2 = 1/10^2= 1/100

8.5 × 10^-2 = 8.5 × 1/100

= 17/200

Final answer = 17000 × 17 / 200

= 1445

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Find the perimeter of triangle ABC with vertices A(6, 3), B(6, - 2) , and C(- 4, 3) .
anyanavicka [17]

Answer:

26.2 units

Step-by-step explanation:

We are given the points/vertices

A(6, 3),

B(6, - 2) , and

C(- 4, 3)

Step two

Let us find the distances between the given points/vertices

A-B =A(6, 3) to B(6,-2)

d=√((x2-x1)²+(y2-y1)²)

Substitute

d=√((6-6)²+(-2-3)²)

d=√(-2-3)²)

d=√(-5)²)

d=5 units

B-C=B(6, - 2) to C(-4, 3)

d=√((x2-x1)²+(y2-y1)²)

Substitute

d=√((-4-6)²+(3+2)²)

d=√(-10)²+(5)²)

d=√100+25

d=√125

d=11.2 units

C-A=C(-4, 3) to A(6, 3)

d=√((x2-x1)²+(y2-y1)²)

Substitute

d=√((6+4)²+(3-3)²)

d=√(10)²

d=√100

d=10 units

Hence the perimeter is 5+11.2+10

P=26.2 units

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Sidana [21]
Answer A. is correct I’m pretty sure
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