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3 years ago

14

Graph each function Y=|x|-1; D:{-4, -2, 0,2,4}

1 answer:

yKpoI14uk [10]3 years ago

4 0

Answer:

bgg ytir

Step-by-step explanation:

bfh the oegrbf rrjrh9e

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What is the imaginary part of z?

Shkiper50 [21]

Answer:

The imaginary part is the multiple of i. It is common practice to use the letter z to stand for a complex number and write z = a + bi where a is the real part and b is the imaginary part. where a is the real part and b is the imaginary part.

Step-by-step explanation:

You can easily check that a complex number z = x + yi times its conjugate x – yi is the square of its absolute value |z|2. Therefore, 1/z is the conjugate of z divided by the square of its absolute value |z|2.

Complex numbers A complex number z is defined as an ordered pair z = (x, y), where x and y are a pair of real numbers.

8 0

3 years ago

An art exhibit at a local museum features several similarly shaped metal cubes welded together to make a sculpture. The smallest

borishaifa [10]

Answer: Length of other edges will be 7.5 inches, 8 inches, 9 inches, 10.5 inches, 12 inches.

Explanation:

Length of smallest cube = 6 inches

Ratio of similarity to the smallest cube is given as follows:

1) 1.25

So, length of other edge will be

$1.25\times 6=7.5\ inches$

2) 4:3

So, the length of other edge will be

$\frac{4}{3}\times 6=8\ inches$

3) 1.5

So, length of other edge will be

$1.5\times 6=9\ inches$

4) 7:4

So, length of other edge will be

$\frac{7}{4}\times 6=10.5\ inches$

5) 2

So, length of other edge will be

$2\times 6=12\ inches$

5 0

3 years ago

Linear functions filling in a table

Fofino [41]

X 1, 2, 3, 4 Y -2, -10, -18, -26

3 0

2 years ago

A case of 24 pairs of the same kind of sports shoes costs a little more than $800. explain wether $28 per pair with tax included

Artemon [7]

You would get 672 dollars for the merch you paid 800 dollars.

Hope this helps!

7 0

2 years ago

Read 2 more answers

Find the following quotients, and write the quotient in standard form. (a)- x^2-9 ÷ x-3 (b)- x^3-27 ÷ x-3 (c) x^4- 81 ÷ x-3

IgorLugansk [536]

Answer:

(a) x+3

(b) $x^2+3x+9$

(c) $(x+3)(x^2+9)$

Step-by-step explanation:

We have given that

(a) $\frac{x^2-9}{x-3}$

From the algebraic identity we know that

$a^2-b^2=(a+b)(a-b)$

So $\frac{x^2-9}{x-3}=\frac{(x+3)(x-3)}{x-3}=x+3$

(b) $\frac{x^3-27}{x-3}$

We know the algebraic identity

$a^3-b^3=(a-b)(a^2+ab+b^2)$

So $\frac{x^3-27}{x-3}=\frac{x^3-3^3}{x-3}=\frac{(x-3)(x^2+3x+9)}{x-3}=x^2+3x+9$

(c) We have given $\frac{x^4-81}{x-3}$

We know the algebraic identity

$a^2-b^2=(a+b)(a-b)$

$\frac{x^4-81}{x-3}=\frac{(x^2)^2-(3^2)^2}{x-3}=\frac{(x^2-9)(x^2+9)}{x-3}=\frac{(x+3)(x-3)(x^2+9)}{x-3}=(x+3)(x^2+9)$

3 0

3 years ago