<span>Martin deposits $200
in a savings account that earns 5% annual interest.
year interest balance
1 200 * 5% 200(1.05)
2 200(1.05) * 5% 200(1.05)^2
3 200(1.05)^2*5% 200(1.05)^3
y 200(1.05)^y
=> m = 200 (1.05)^y
four years later,
cary deposits $200 in an account earning the same interest.
</span>
<span><span>year interest balance
5 200 * 5% 200(1.05)
6 200(1.05) * 5% 200(1.05)^2
7 200(1.05)^2*5% 200(1.05)^3
y 200(1.05)^(y-4)
=> c = 200(1.05)^ (y-4)
</span>
Answer:
Martin: 200(1.05)^y
Cary: 200(1.05)^(y–4)</span>
Answer:

Step-by-step explanation:

Answer:
The 5 unknown are 1 quarter, 3 dimes, and 1 penny.
Answer:
<u>The probability that a randomly selected boy in school can run the mile in less than 348 seconds is 1.1%.</u>
Step-by-step explanation:
1. Let's review the information provided to us to answer the question correctly:
μ of the time a group of boys run the mile in its secondary- school fitness test = 440 seconds
σ of the time a group of boys run the mile in its secondary- school fitness test = 40 seconds
2. Find the probability that a randomly selected boy in school can run the mile in less than 348 seconds.
Let's find out the z-score, this way:
z-score = (348 - 440)/40
z-score = -92/40 = -2.3
Now let's find out the probability of z-score = -2.3, using the table:
p (-2.3) = 0.0107
p (-2.3) = 0.0107 * 100
p (-2.3) = 1.1% (rounding to the next tenth)
<u>The probability that a randomly selected boy in school can run the mile in less than 348 seconds is 1.1%.</u>