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Serhud [2]
3 years ago
14

If a veterinarian, noticed that she only had 12 ounces of cat treats left. So, she bought a new 3-pound jar. If she uses about 6

ounces of cat treats every week, in how many weeks will she run out?
Mathematics
2 answers:
azamat3 years ago
6 0
Answer:

10 weeks before she run out
Readme [11.4K]3 years ago
5 0

Answer:

It would be 10 weeks before she ran out

You might be interested in
Que How does your tessellation with triangles relate to hexagons and tessellating the plane? Type your response in the space bel
madreJ [45]

For a regular tessellation, the shapes can be duplicated infinitely to fill a plane such that there is no gap. The only shapes that can form regular tessellations are equilateral traingle(all sides are equal. This means that it can be turned to any side and it would remain the same), square and regular hexagon. Looking at the given options, we have

Shape Tessellate?

Octagon No

Hexagon Yes

Pentagon No

Square Yes

Triangle No(unless it is specified that it is an equilateral triangle)

5 0
1 year ago
A gym has 2kg and 5kg weights. There are 10 disks in all. The total weight of 2kg and 5kg disks is equal to 29kg. Find the numbe
Simora [160]

Answer:

no of 5 kg disks is 3, and no of 2 kg disks is (10-3) i.e. 7

Step-by-step explanation:

Let the no of 2kg disks be a.

Let no of 5 kg disks be b.

2a+5b=29

a+b=10

Using substitution, we have

2(10-b) + 5b=29

20-2b+5b=29

20+3b=29

3b=9

b=3

So no of 5 kg disks is 3, and no of 2 kg disks is (10-3) i.e. 7

6 0
3 years ago
NEED IT ASAP What is the value of x in the diagram below? A.18/ ROOT 3 B.18 ROOT 2/ROOT 3 C.18 ROOT 3/ ROOT 2 D. 18 ROOT 2
Ostrovityanka [42]

Answer:

x = B. 18 ROOT 2/ROOT 3

Step-by-step explanation:

There are two Triangles in the diagram above.

Step 1

We would solve for Triangle A First

Using Trigonometric function Cosine

cos θ = adjacent /hypotenuse

θ = 30°

Adjacent = 9 units

Hypotenuse = unknown

cos 30= 9/ Hypothenuse

Cross Multiply

cos 30 × Hypotenuse = 9

Hypotenuse = 9 / cos 30

cos 30 in surd form = √3/2

Hypotenuse = 9/√3/2

Hypotenuse = 9 × 2/√3

= 18/√3 units

Step 2

We would solve for the upper triangle = Triangle B

We are looking for x

θ = 45°

For Triangle B, the Hypotenuse we solved for in Triangle A is equivalent to the adjacent in Triangle B

Therefore ,

Hypotenuse for Triangle A = Adjacent side for Triangle B

θ = 45°

Adjacent = 18/√3 units

Hypotenuse = x = unknown

We would solve for this using Trigonometric function cosine

cos 45 = 18/√3 units / Hypothenuse

Cross Multiply

cos 45 × Hypotenuse = 18/√3 units

Hypotenuse = 18/√3 units / cos 45

cos 45 in surd form = 1/√2

Subtituting, we have

Hypotenuse (x) = 18/√3 units / 1/√2

Hypotenuse (x) = 18/√3 units ×√2/1

= 18× √2/ √3 units

= 18 √2/√3 units

Therefore x = Option B. 18 ROOT 2/ROOT 3

3 0
2 years ago
If the distance between A(0, 4) and B(3,a) is 5 units then find the value of a.​
Anna007 [38]

Answer:

Step-by-step explanation:

a = 0

So that AOB makes a right triangle with sides 3-4-5

4 0
2 years ago
Read 2 more answers
Find the exact value of sin (arccos (3/5)). For full credit, explain your reasoning.
zloy xaker [14]
The equation for cosine is <span><span><span>cos<span>(x)</span></span>=<span>Adjacent/Hypotenuse
</span></span></span>The inside trig function is <span><span>arccos<span>(<span>3/5</span>)</span></span></span>, which means <span><span><span>cos<span>(x)</span></span>=<span>3/5</span></span></span>. Comparing <span><span><span>cos<span>(x)</span></span>=<span>Adjacent/Hypotenuse</span></span></span> with <span><span><span>cos<span>(x)</span></span>=<span>3/5
</span></span></span>
Find <span><span>Adjacent=3</span></span> and <span><span>Hypotenuse=5.
</span></span>Then, using the Pythagorean theorem, find <span><span>Opposite=?
</span></span>a² = c² - b²
a² = 5² - 3² = 25 - 9 = 16
a = √16 = 4

<span><span>Adjacent=3</span></span><span><span>Opposite=4</span></span><span><span>Hypotenuse=5
</span></span><span>
Plug in the value for sin(x) = opposite/hypotenuse

sin(x) = 4/5 </span>
6 0
3 years ago
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