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Serhud [2]
3 years ago
14

If a veterinarian, noticed that she only had 12 ounces of cat treats left. So, she bought a new 3-pound jar. If she uses about 6

ounces of cat treats every week, in how many weeks will she run out?
Mathematics
2 answers:
azamat3 years ago
6 0
Answer:

10 weeks before she run out
Readme [11.4K]3 years ago
5 0

Answer:

It would be 10 weeks before she ran out

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What integer <br> Describes a profit of <br> $650? Please show your work.
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+$650 because there is no loss of money
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1. as.at<br>2. (a/b)2 (a/b)<br>8<br>3. (3)-5<br>4. (x/y)"<br>5. (2m4n3)5<br>​
Nikolay [14]
1- I didn't understand it

2).. (a/b)² (a/b)⁸

= (a/b)²+⁸ = (a/b)¹⁰

3) 3-⁵ = 1/3⁵ = 1/243

4) (x/y)"

d/dx (x/y) = (1/y)
d/dx (1/y) = 0

5) (2m⁴n³)⁵

= 2⁵ × (m⁴)⁵ × (n³)⁵

= 32 × m²⁰ × n¹⁵

= 32m²⁰n¹⁵
5 0
3 years ago
Dividing complex numbers
Neporo4naja [7]

Answer:

DIVIDING COMPLEX NUMBERS

<em>Dividing complex numbers is a little more complicated than addition, subtraction, and multiplication of complex numbers because it is difficult to divide a number by an imaginary number. For dividing complex numbers, we need to find a term by which we can multiply the numerator and the denominator that will eliminate the imaginary part of the denominator so that we end up with a real number in the </em><em>DENOMINATOR</em>

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3x + 2x divided by 4-2
Harlamova29_29 [7]
The answer is 5x/2 because all you have to do is add 3x + 2x too make 5x and take 4-2 which is 2 and since it can't be simplified any more, just do 5x/2. Hope this helped! :)
3 0
3 years ago
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The data show the traveler spend- ing in billions of dollars for a recent year for a sample of the states. Find the range, varia
Svetllana [295]

Solution :

Given data :

20.1     33.5     21.7      58.4     23.2     110.8     30.9

24.0    74.8     60.0

n = 10

Range : Arranging from lowest to highest.

20.1,   21.7,   23.2,    24.0,   30.9,    33.5,    58.4,    60.0,    74.8,   110.8

Range = low highest value - lowest value

           = 110.8 - 20.1

           = 90.7

Mean = $\frac{\sum x}{n}$

         $=\frac{20.1+21.7+23.2+24.0+30.9+33.5+58.4+60.0+74.8+110.8}{10}$

          $=\frac{457.4}{10}$

         $=45.74$

Sample standard deviation :

$S=\sqrt{\frac{1}{n-1}\sum(x-\mu)^2}$

$S=\sqrt{\frac{1}{10-1}(20.1-45.74)^2+(21.7-45.74)^2+(23.2-45.74)^2+(24.0-45.74)^2+(30.9-45)^2}$  

      \sqrt{(33.5-45.74)^2+(58.4-45.74)^2+(60.0-45.74)^2+(74.8-45.74)^2+(110.8-45.74)^2}

$S=\sqrt{\frac{1}{9}(657.4+577.9+508.0+472.6+220.2+149.8+160.2+203.3+844.4+4232.8)}$$S=\sqrt{\frac{1}{9}(8026.96)}$

$S=\sqrt{891.88}$

S = 29.8644

Variance = S^2

               =(29.8644)^2

               = 891.8823

6 0
3 years ago
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