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3 years ago

What is the period of the sinusoidal function?

Mathematics

1 answer:

ehidna [41]3 years ago

8 0

Answer:The period of the sine curve is the length of one cycle of the curve. The natural period of the sine curve is 2π. So, a coefficient of b=1 is equivalent to a period of 2π. To get the period of the sine curve for any coefficient b, just divide 2π by the coefficient b to get the new period of the curve.

Step-by-step explanation:

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6 1/3+8 3\4<br><br>please help

gulaghasi [49]

Answer:

181/12 or 15 1/12

Step-by-step explanation:

8 0

3 years ago

How do I solve this using the substitution method for finding anti derivatives?

rewona [7]

A bit blurry, but if I'm making it out correctly, that's

$\displaystyle\int t\sqrt{(t^2-9)^3}\,\mathrm dt=\int t(t^2-9)^{3/2}\,\mathrm dt$

Set $u=t^2-9$ . Then $\mathrm du=2t\,\mathrm dt$ , or $t\,\mathrm dt=\dfrac{\mathrm du}2$ . The integral is then equivalent to

$\displaystyle u^{3/2}\dfrac{\mathrm du}2=\frac12\int u^{3/2}\,\mathrm du$
$=\dfrac12\dfrac{u^{5/2}}{\frac52}+C$
$=\dfrac12\times\dfrac25u^{5/2}+C$
$=\dfrac15u^{5/2}+C$
$=\dfrac15(t^2-9)^{5/2}+C$

6 0

3 years ago

Please help! Thank you!

viva [34]

Answer:

Step-by-step explanation: im not extremely sure about this one though but the x coordinate is nine away from every coordinate of defc and the way it goes left means that the x is negative, the y coordinates of defc prime is positive because it moves up from defc. hope this helps

4 0

3 years ago

Which of the following inequalities is graphed above?

kobusy [5.1K]

Answer:

1st option

y=-3/8x+3

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3 years ago

The function shown in the graph is A) f(x) = x - 1 B) f(x) = 2x - 1 C) f(x) = x - 0.5 D) f(x) = 2x - 0.5

ryzh [129]

Answer:

Step-by-step explanation:

B because the y-intercept is (0,-1) and another point is (5,9). Using the slope formula, 10/5=2 so the right equation is B.

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3 years ago