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laila [671]
3 years ago
7

the cinma charges x dollars for an afternoon show and an additional $3.00 to see the 3D. Write an expression to show the cost of

five regular tickets and three 3D tickets. Slimpify the expression
Mathematics
1 answer:
Vikentia [17]3 years ago
4 0
5x+9 is the equation
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Can anyone just explain how to do a distant rate time problems because I'm confused about them
Ulleksa [173]

Answer:

The formula for distance problems is: distance = rate × time or d = r × t. Things to watch out for: Make sure that you change the units when necessary. For example, if the rate is given in miles per hour and the time is given in minutes then change the units appropriately.

Step-by-step explanation:

Here is an example.

Two cars started from the same point, at 5 am, traveling in opposite directions at 40 and 50 mph respectively. At what time will they be 450 miles apart?

After t hours the distances D1 and D2, in miles per hour, travelled by the two cars are given by

D1 = 40 t and D2 = 50 t

After t hours the distance D separating the two cars is given by

D = D1 + D2 = 40 t + 50 t = 90 t

Distance D will be equal to 450 miles when

D = 90 t = 450 miles

To find the time t for D to be 450 miles, solve the above equation for t to obtain

t = 5 hours.

5 am + 5 hours = 10 am

4 0
3 years ago
Pls do answer correct for brainliest
nadya68 [22]
1 3/4 fraction form or 1.75 in decimal form
8 0
2 years ago
Read 2 more answers
Write the equation for the inverse of y=4arccot(
garri49 [273]
I think you meant "y = 4 arccot (x)."  

This is equivalent to:

 y
---- = arccot x
 4

and so cot (y/4) = x
8 0
3 years ago
Tara is a little worried about this breakdown because she knows the drug will likely affect younger women differently than older
Thepotemich [5.8K]

Answer:

NOT TO WASTE POINTS BUT PLEASE DO NOT USE THAT LINK ABOVE

Step-by-step explanation:

IT TRACKS YOU

3 0
3 years ago
Read 2 more answers
How many positive integers $n$ satisfy $127 \equiv 7 \pmod{n}$? $n=1$ is allowed.
Svetllana [295]
Naturally, any integer n larger than 127 will return 127\equiv127\mod n, and of course 127\equiv0\mod127, so we restrict the possible solutions to 1\le n.

Now,

127\equiv7\mod n

is the same as saying there exists some integer k such that

127=nk+7

We have

\implies 120=nk

which means that any n that satisfies the modular equivalence must be a divisor of 120, of which there are 16: \{1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120\}.

In the cases where the modulus is smaller than the remainder 7, we can see that the equivalence still holds. For instance,

127=21\cdot6+1\iff127\equiv1\equiv7\mod6

(If we're allowing n=1, then I see no reason we shouldn't also allow 2, 3, 4, 5, 6.)
5 0
3 years ago
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