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Leokris [45]
4 years ago
14

Beth has 30 days to train for the Olympics. She swims 20 laps on the first day, then each day after that she swims two more laps

that the previous day. So, she swims 22 laps on the second day, 24 laps on the third day, and so on.
Mathematics
1 answer:
hjlf4 years ago
7 0
Wait, what’s the question?
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Customers can pick their own blueberries at blueberry hill. They pay$5 to enter the patch and $4 per pound for the blueberries t
Anastaziya [24]
Y = total costs to get the berries

x = pounds of berries.

\bf \stackrel{cost}{y}=\stackrel{\textit{4 bucks per pound}}{4x}+\stackrel{\textit{fixed rate just to step in the market}}{5}

bearing in mind that the $5 is just to get in, so is only paid once, whilst the pounds of berry will vary.
7 0
3 years ago
A movie made $28 million in its first week in the box office, but only $6 million in its second week. How much more money did it
4vir4ik [10]

Answer:

$22 million

Step-by-step explanation:

28 mil-6 mil

5 0
3 years ago
Is it possible for a 5 digit number to be rounded to a 6 digit number
IrinaK [193]
When we round a number the new rounded <span>number is </span>simpler but the value is kept close to what it was. The common method for rounding numbers is the following: we d<span><span>ecide which is the last digit to keep and l</span><span>eave this digit the same the same if the next digit is less than 5 or increase it by 1 if the next digit is bigger than 5.
</span></span>Because the next digit matter, it is not possible for a 5 digit number to be rounded to 6 digit number. 
5 0
3 years ago
Read 2 more answers
If the value of third order determinant is 11. Then what is the value of the determinant formed by its cofactors.
nordsb [41]

Answer:

146.41

Step-by-step explanation:

third order determinant = determinant of 3×3 matrix A

given ∣A∣=11

det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)

=det(adjacent of A)

{det (cofactor matrix of A)}  ^2  = {det (adjacent of A)} ^2

 

(Using for an n×n det (cofactor matrix of A)=det (A)^n−1 )

we get

det (cofactor matrix of A)^2  = {det(A)  ^3−1 }^2

 

=(11)^2×2  = 11^4

 =146.41

5 0
3 years ago
Sammy watched
faltersainse [42]

Answer:

5/12

Step-by-step explanation:

4 and 3 gcf is 12
8/12 - 3/12 = 5/12

3 0
2 years ago
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